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Marat540 [252]
3 years ago
5

Robert lifts a 150-newton bucket of water 0.5 meters in 3 seconds. What is the amount of work done on the

Physics
1 answer:
Nikitich [7]3 years ago
7 0

Answer:

c. 75 joules

Explanation:

Work done(joules)=Force(newton)×Distance(meters)

Given: force=150-newton, Distance=0.5 meters

∴Work done=150×0.5=75 joules.

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How could you increase the gravitational potential energy between yourself and Earth?
Tamiku [17]
Gravitational Potential Energy, GPE = mgh

Where m is your mass in kg, g is acceleration due to gravity = 9.8 m/s², and h is the height in m.

The only value that be controlled here is the height h.  The mass is constant, and acceleration due to gravity at that place is constant.

But h can be varied.

Hence to increase the gravitational potential energy between yourself and Earth is to increase the height h.

This can be done by climbing up a table, or climbing up a building through the stairs, or by using a lift.
5 0
3 years ago
Gravitational pull is determined by ____
sergij07 [2.7K]
The correct answer is mass

8 0
4 years ago
Read 2 more answers
The most important identifying feature of a parallel circuit is that:
ValentinkaMS [17]
Current is split among different branches of wires, or voltage is equal throughout?
6 0
3 years ago
It takes 26.5 N to just pull a 72 kg sled across snow. What is the coefficient of friction?
Shtirlitz [24]
Assuming g = 10, the weight of the sled is 720N.

If it takes 26.5N to just pull the sled, then the frictional force f is 26.5N in the opposite direction.

f = μ*720N
26.5N = μ*720N
μ = 26.5N/720N = 0.037 (2 s.f.)

3 0
3 years ago
The front of a 1300 kg car is designed to absorb the shock of a collision by having a "crumple zone" in which the front 1.20 m o
Novay_Z [31]

Answer:

<em>The collision last 0.83 s</em>

Explanation:

Using the equation of motion,

S = (v+u)t/2 ........................ Equation 1

making t the subject of the equation,

t = 2S/(v+u)..................... Equation 2

Where S = distance, v = final velocity, u = initial velocity, t = time

Given: v = 0 m/s, u = 29.0 m/s, S = 1.20 m,

Substituting these values into equation 2

t = 2(1.2)/(29+0)

t = 2.4/29

t = 0.83 sec.

<em>Thus the collision last 0.83 s</em>

7 0
3 years ago
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