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melomori [17]
3 years ago
9

Jean-Paul Sovique, the famous sculptor, is building a solid conical sculpture. He has 1,178.1 cubic feet of clay to work with, a

nd he wants his sculpture to be three times as high as its radius. What will the radius and height of his cone be?
Mathematics
1 answer:
faust18 [17]3 years ago
7 0

Answer:

Radius = 7.21 feet.

Height = 21.63 feet

- to the nearest hundredth.

Step-by-step explanation:

Let the radius be r feet, then the height will be 3r feet.

So the volume = 1,178.1 = 1/3 π r^2 h

1.178.1 = 1/3  π r^2 3r

1/3 π 3 r^3 = 1178.1

 π r^3 = 1178.1

r^3 = 1178.1/ π

r^3 =   375

r = 7.211 feet.

So the height = 3 * 7.211 ft

= 21.633 ft

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Answer:

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2y - 5 = 95

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x = 12

x=12 and y=50 so

12 + 50 = 62

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In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

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Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

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Answer:

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Step-by-step explanation:

180/5=36 miles per gallon

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Answer:

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Step-by-step explanation:

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this means that the power of then used should have 3 0's

making the power of ten 1,000

3 0
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