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Amiraneli [1.4K]
4 years ago
14

Please help, I'm really confused

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
7 0

Empirical probability is computed by running an experiment multiple times (in this case, asking the same question to many people), and then computing the ratio

\dfrac{\text{good cases}}{\text{all cases}}

In this case, 236 people over 991 said that they checked the portfolio daily, so the empirical probability is

P(\text{daily check})=\dfrac{236}{991}

Which you can round as 0.238, i.e. 23.8%.

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4 years ago
Someone please help me it's worth 35 points
Zigmanuir [339]
Question 1)
I assume it asks about the circumference (of only the circle arc)
C=r*2*pi
r=2
-> C=4pi

1 Quarter only of the circle: C/4=pi=3.1

if it's the perimeter of the shape then you need to add the two 2in sides

C=3.1+2*2=7.1

2)
C=r*2*pi, but not a full circle, only semi-> divide by 2-> C=r*pi
r=30
C=30pi=94.2

3)
the radius of the semicircle is 6/2=3mm
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4)
C=2r*pi
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4 0
3 years ago
If the area of a rectangle with width X can be represented with the expression a(x) = x(14-x), what is the perimeter of the rect
dimaraw [331]

Expression for perimeter is 2(14-x + x) = 28

<u>Step-by-step explanation:</u>

Step 1:

Given expression for area of the rectangle = a(x) = x(14-x) where x is the width. Then length = 14-x since area = length × width

Step 2:

Find expression for perimeter of the rectangle.

Perimeter of the rectangle = 2(length + width) = 2(14 - x + x) = 2 × 14 = 28

7 0
4 years ago
What two prime numbers total 31​
Llana [10]

Answer:

2, 29

Step-by-step explanation:

The prime numbers are 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89, and 97.

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3 years ago
Evaluate<br> (9n +8m) <br> —————<br> 2j <br> when n = 4, m = -2 and j = 5<br> 2j
Anuta_ua [19.1K]

Answer:

<h2>2</h2>

Step-by-step explanation:

<h3>Let n= 4, m= -2 and j= 5</h3><h3 /><h3>(9n + 8m)/2j</h3><h3>= 9(4) + 8(-2)/2(5)</h3><h3>= 36 + (-16)/10</h3><h3>= 20/10</h3><h3>= 2</h3><h3 />

\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}

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