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vladimir1956 [14]
4 years ago
6

If the area of a rectangle with width X can be represented with the expression a(x) = x(14-x), what is the perimeter of the rect

angle?
Mathematics
1 answer:
dimaraw [331]4 years ago
7 0

Expression for perimeter is 2(14-x + x) = 28

<u>Step-by-step explanation:</u>

Step 1:

Given expression for area of the rectangle = a(x) = x(14-x) where x is the width. Then length = 14-x since area = length × width

Step 2:

Find expression for perimeter of the rectangle.

Perimeter of the rectangle = 2(length + width) = 2(14 - x + x) = 2 × 14 = 28

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Pls help me! Due in like, 5 minutes and I am stuck on this question! 20 points and brainliest!
MrRa [10]

Answer:

9 times

Step-by-step explanation:

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3 years ago
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Shtirlitz [24]
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7 0
4 years ago
Priya has completed 9 eczema questions.THis is 60% of the questions on the exam? how many questions are on the exam?
qwelly [4]

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7 0
3 years ago
One quantity of interest is maximum height. What other quantity might be of interest?
3241004551 [841]

The other quantity which might be of interest is initial velocity

<h3>What is maximum height?</h3>

The maximum height of the object can be defined as the highest vertical position along its trajectory line.

The range of the projectile is also known as the horizontal displacement of the projectile. It is largely dependent on the initial velocity of the object.

If;

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  • θ = angle of the initial velocity from the horizontal plane (radians or degrees).

Maximum height of projectile is given by the formula:

H = \frac{vo^2sin^2\alpha }{2g}

From this, we can deduce that another quantity of interest is initial velocity

Thus, the other quantity which might be of interest is initial velocity

Learn more about maximum height here:

brainly.com/question/12446886

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4 0
2 years ago
X/-2=4, X/3+13=13, Z/2+2=4 plz show ur work and explain how u did it
AVprozaik [17]
\dfrac{x}{-2}=4\ \ \ |multiply\ both\ sides\ by\ (-2)\\\\(-2)\cdot\dfrac{x}{-2}=(-2)\cdot4\\\\\boxed{x=-8}\\\\\dfrac{x}{3}+13=13\ \ \ |subtract\ 13\ from\ both\ sides\\\\\dfrac{x}{3}+13-13=13-13\\\\\dfrac{x}{3}=0\ \ \ |multpily\ both\ sides\ by\ 3\\\\\not3^1\cdot\dfrac{x}{\not3_1}=0\\\\\boxed{x=0}

\dfrac{z}{2}+2=4\ \ \ |subtract\ 2\ from\ both\ sides\\\\\dfrac{z}{2}+2-2=4-2\\\\\dfrac{z}{2}=2\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\\not2^1\cdot\dfrac{z}{\not2_1}=2\cdot2\\\\\boxed{z=4}
6 0
3 years ago
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