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2 years ago

Please help me with this

Mathematics

2 answers:

S_A_V [24]2 years ago

4 0

Answer:

x = 4.4 in

Step-by-step explanation:

The segment from the centre of the circle to the chord is a perpendicular bisector, hence

7.4 ÷ 2 = 3.7

Consider the right triangle with legs 3.7 and 2.4 and hypotenuse x

Using Pythagoras' identity in the right triangle, then

x² = 2.4² + 3.7² = 5.76 + 13.69 = 19.45

Take the square root of both sides

x = $\sqrt{19.45}$ ≈ 4.4 in

mezya [45]2 years ago

3 0

Answer:

4.4 in

Step-by-step explanation:

If a radius is perpendicular to a chord, it bisects that chord. You can use Pythagorean theorem here

${3.7}^{2} + {2.4}^{2} = {x}^{2}$

Once solved you'll find x to be roughly 4.4 in

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$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

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We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

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Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

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$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

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