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Lina20 [59]
2 years ago
6

Ayanna plans to bake 3 types of cookies to take to a party. She needs to be sure that she has enough flour. The chocolate cookie

s use
1 3/4
cups of flour, the sugar cookies use
3 2/3
cups of flour, and the oatmeal spice cookies require
1 7/8
cups of flour. Which is the BEST estimate of the total amount of flour she will need?
Mathematics
2 answers:
wel2 years ago
8 0
Since you need an estimate, you can round up the cups of Fluor you need. So, 1 3/4 rounds to 2 cups, 3 2/3 rounds to 4 cups and 1 7/8 rounds to 2 cups.
2+4+2 = 8 cups is the best estimate
djyliett [7]2 years ago
7 0
The children brought 2+1+114=414 cups of flour and 14+12+34=112 cups of butter.

They have enough flour for

414÷34===174×43173523
batches and they have enough butter for

112÷13===32×3192412
batches, so the butter is the limiting factor. Thus, they can make 4 whole batches of a dozen cookies each.
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5 + x - 5 = x

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4 0
3 years ago
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djverab [1.8K]

Answer:

64 visitors (other 80%)

Step-by-step explanation:

20% of visitors of 80 visitors is 16

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3 years ago
Factor completely.<br> 5x4 + 35x3– 150x2
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5x^4+35x^3-150x^2

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3 0
3 years ago
The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation
Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

<u><em>Let X = weights of adult male birds of a certain species</em></u>

So, X ~ Normal(\mu=27.5,\sigma^{2} =1.1^{2})

The z score probability distribution for normal distribution is given by;

                                 Z = \frac{ X-\mu}{\sigma } }  ~ N(0,1)

where, \mu = population mean weight = 27.5 grams

           \sigma = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

          <u>Z score</u> =  \frac{ X-\mu}{\sigma } } = \frac{ 29.37-27.5}{1.1 } }

                                    =  <u>1.7</u>

                       

4 0
3 years ago
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ArbitrLikvidat [17]
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Therefore, P(e3) = 0.3
3 0
3 years ago
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