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marissa [1.9K]
3 years ago
12

A rectangular laboratory tray is 3/5 feet by 7/6 feet. What is the area

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0
7/10 is the simplest form of the fraction when you multiply (3/5) by (7/6)
You might be interested in
HELP ME PLEASE!!!!!!
Deffense [45]

9514 1404 393

Answer:

  -2x +4

Step-by-step explanation:

We can write the polynomial p(x) in terms of the factors (x+2) and (x-3) as ...

  p(x) = (x+2)(x-3)q(x) +ax +b

Where ax+b is the remainder from division by x^2 -x -6 = (x+2)(x-3). The values of 'a' and 'b' can be found from ...

  p(-2) = 8 = -2a +b

  p(3) = -2 = 3a +b

Subtracting the first equation from the second gives ...

  (3a +b) -(-2a +b) = (-2) -(8)

  5a = -10

  a = -2

Then the first equation tells us ...

  8 = -2(-2) +b

  4 = b

So, the remainder from division by (x^2 -x -6) is (-2x +4).

5 0
3 years ago
Find the perimeter of diameter 3.5 cm​
sergiy2304 [10]

Answer: I am assuming it’s of a circle? So the answer would be rounded to 11.

Step-by-step explanation:

3 0
3 years ago
a rectangular patio has a perimeter of 60 feet. if the length of the patio is 3 feet less than twice the width, find the dimensi
Juli2301 [7.4K]
P = 2(L + W)
P = 60
L = 2W - 3

60 = 2(2W - 3 + W)
60 = 2(3W - 3)
60 = 6W - 6
60 + 6 = 6W
66 = 6W
66/6 = W
11 = W <=== the width is 11 ft

L = 2W - 3
L = 2(11) - 3
L = 22 - 3
L = 19 <=== the length is 19 ft
6 0
4 years ago
I neeed heeelppppppppp
zheka24 [161]

Answer:

P(x) =-2x^{2} + 304x  - 8510

x = 37 smallest B.E.P

Step-by-step explanation:

P = R - E

P =-2x^{2} + 317 x

E =  13x + 8510

P =-2x^{2} + 317 x - 13x - 8510

P(x) =-2x^{2} + 304x  - 8510

B.E.P.(X) where  R=E

-2x^{2} + 304 x  -  8510 = 0

2(x-37)(x-115)

4 0
3 years ago
A ball is launched upward from a height 40 feet above ground level. The ball’s height at t seconds is given by -16t^2=128=40 .
Nesterboy [21]

Answer:

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

Step-by-step explanation:

<u><em>The correct question is</em></u>

A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?

we have

h(t)=-16t^{2}+128t+40

so

For h(t)=100 ft

substitute in the equation and solve for x

-16t^{2}+128t+40=100

-16t^{2}+128t-60=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+128t-60=0

so

a=-16\\b=128\\c=-60

substitute in the formula

x=\frac{-128(+/-)\sqrt{128^{2}-4(-16)(-60)}} {2(-16)}

x=\frac{-128(+/-)\sqrt{12,544}} {-32}

x=\frac{-128(+/-)112} {-32}

x=\frac{-128(+)112} {-32}=0.5

x=\frac{-128(-)112} {-32}=7.5

therefore

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

7 0
4 years ago
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