9514 1404 393
Answer:
-2x +4
Step-by-step explanation:
We can write the polynomial p(x) in terms of the factors (x+2) and (x-3) as ...
p(x) = (x+2)(x-3)q(x) +ax +b
Where ax+b is the remainder from division by x^2 -x -6 = (x+2)(x-3). The values of 'a' and 'b' can be found from ...
p(-2) = 8 = -2a +b
p(3) = -2 = 3a +b
Subtracting the first equation from the second gives ...
(3a +b) -(-2a +b) = (-2) -(8)
5a = -10
a = -2
Then the first equation tells us ...
8 = -2(-2) +b
4 = b
So, the remainder from division by (x^2 -x -6) is (-2x +4).
Answer: I am assuming it’s of a circle? So the answer would be rounded to 11.
Step-by-step explanation:
P = 2(L + W)
P = 60
L = 2W - 3
60 = 2(2W - 3 + W)
60 = 2(3W - 3)
60 = 6W - 6
60 + 6 = 6W
66 = 6W
66/6 = W
11 = W <=== the width is 11 ft
L = 2W - 3
L = 2(11) - 3
L = 22 - 3
L = 19 <=== the length is 19 ft
Answer:
P(x) =
+ 304x - 8510
x = 37 smallest B.E.P
Step-by-step explanation:
P = R - E
P =
+ 317 x
E = 13x + 8510
P =
+ 317 x - 13x - 8510
P(x) =
+ 304x - 8510
B.E.P.(X) where R=E
+ 304 x - 8510 = 0
2(x-37)(x-115)
Answer:
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
Step-by-step explanation:
<u><em>The correct question is</em></u>
A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?
we have

so
For h(t)=100 ft
substitute in the equation and solve for x


The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
therefore
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec