Answer:
Table 1 and 2 represent a function
Step-by-step explanation:
Given
<em>Table 1</em>
x 5 10 11
y 3 9 15
<em></em>
<em>Table 2</em>
x 5 10 11
y 3 9 9
<em>Table 3</em>
x 5 10 10
y 3 9 15
Required
Determine which of the tables represent that y is a function of x
For a relation to be a function; the x values must be unique.
In other words, each x value must not be repeated;
Having said that;
Analyzing Table 1
<em>Table 1</em>
x 5 10 11
y 3 9 15
<em></em>
Note that the x rows are unique as no value were repeated;
Hence, Table 1 is a function
<em>Table 2</em>
x 5 10 11
y 3 9 9
Note that the x rows are unique as no value were repeated;
Hence, Table 2 is a function
<em>Table 3</em>
x 5 10 10
y 3 9 15
Note that the x rows are not unique because 10 was repeated twice;
Hence, Table 3 is not a function
Answer:
-2-h
Step-by-step explanation:
It doesn't hurt to follow directions.
![q=\dfrac{f(3+h)-f(3)}{h}=\dfrac{(5 +4(3+h)-(3+h)^2)-(5 +4(3)-(3)^2)}{h}\\\\=\dfrac{5-5+4(3+h-3)-((3+h)^2-3^2)}{h}=\dfrac{4h-(6h+h^2)}{h}\\\\=\dfrac{-2h-h^2}{h}=\boxed{-2-h}](https://tex.z-dn.net/?f=q%3D%5Cdfrac%7Bf%283%2Bh%29-f%283%29%7D%7Bh%7D%3D%5Cdfrac%7B%285%20%2B4%283%2Bh%29-%283%2Bh%29%5E2%29-%285%20%2B4%283%29-%283%29%5E2%29%7D%7Bh%7D%5C%5C%5C%5C%3D%5Cdfrac%7B5-5%2B4%283%2Bh-3%29-%28%283%2Bh%29%5E2-3%5E2%29%7D%7Bh%7D%3D%5Cdfrac%7B4h-%286h%2Bh%5E2%29%7D%7Bh%7D%5C%5C%5C%5C%3D%5Cdfrac%7B-2h-h%5E2%7D%7Bh%7D%3D%5Cboxed%7B-2-h%7D)
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Steps: substitute 3+h and 3 for x in the definition of f(x) and simplify the result.
23 the answer is Bbbbbbbbbbbbbbbbbbbb
Answer:
B, "The graph of g(x) will eventually exceed the graph of f(x)."
Step-by-step explanation: