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san4es73 [151]
2 years ago
13

Costs that do not change in total over wide ranges of volume. 2. Technique that estimates profit or loss results when conditions

change. 3. The sales level at which operating income is zero. 4. Drop in sales a company can absorb without incurring an operating loss. 5. Combination of products that make up total sales. 6. Net sales revenue minus variable costs. 7. Describes how a cost changes as volume changes. 8. Costs that change in total in direct proportion to changes in volume. 9. The band of volume where total fixed costs and variable cost per unit remain constant.
Business
1 answer:
likoan [24]2 years ago
3 0

Complete Question:

Match the terms with the correct definitions.

Answer:

1. Fixed costs: Costs that do not change in total over wide ranges of volume.

2. Sensitivity analysis: Technique that estimates profit or loss results when conditions change.

3. Breakeven point: The sales level at which operating income is zero.

4. Margin of safety: Drop in sales a company can absorb without incurring an operating loss.

5. Sales mix: Combination of products that make up total sales.

6. Contribution margin: Net sales revenue minus variable costs.

7. Cost behavior: Describes how a cost changes as volume changes.

8. Variable costs: Costs that change in total in direct proportion to changes in volume.

9. Relevant range: The band of volume where total fixed costs and variable cost per unit remain constant.

Explanation:

It is required that each term are matched with their respective correct definitions. The terms are generally associated with business and sales management.

For instance, fixed costs are indirect costs that do not change in total over wide ranges of volume and irrespective of the level of output (goods and services) e.g rent, salaries, property tax, insurance, depreciation etc.

Also variable costs are costs that change in total in direct proportion to changes in volume of goods and services e.g sales commission, utility costs, raw materials costs, credit card fees, direct labour costs etc.

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The correct answer is mass production. Mass production is being defined as having to manufacture products in large quantities by which they are likely utilized by an assembly of line technology. This is a process by which it creates similar products in large numbers.

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Which of the following best describes a trial balance?
Lubov Fominskaja [6]

Answer:

A

Explanation:

In the accounting process extracting a trial balance is the final step.

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An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

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The receiving report is usually used by a business to record the details of the products that are received from suppliers. The record documents what is owned to supplier based on the number of goods accepted and the ones that are returned.<span />
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Answer:

c. money supply to rise. To reduce the impact of this the Fed could sell Treasury bonds.

Explanation:

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