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Rom4ik [11]
3 years ago
11

Solve the formula C = πd for d

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

d = \frac{C}{\pi}

Step-by-step explanation:

C= \pi d\\

Isolate d ; Divide both sides of the equation by \pi

\frac{C}{\pi} = \frac{\pi d}{\pi }

Simplify

\frac{C}{\pi} = d\\\\d = \frac{C}{\pi}

Note; Another formula for d(diameter) =

2\times radius

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The senior classes at High School A and High School B planned separate trips to Lake Compounce. The senior class at High School
storchak [24]

Answer:

Number of students in vans =15 and bus =46

Step-by-step explanation:

use variables for the vans and buses

let x= vans and y=buses

Now solve the 2 equations simultaneously

<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>

6x+7y=412..........1

6x+9y=504.........2

make x the subject of one equation

and label it equation 3

6x=412—7y

x =  \frac{206}{3}  -  \frac{7y}{6} .............3

subs 3 into 2

6( \frac{206}{3}  -  \frac{7y}{6} ) + 9y = 504

412 - 7y + 9y = 504

- 7y + 9y = 504 - 412

2y = 92

y = 46...................4

subs 4 into 1

6x + 7(46) = 412

6x + 322 = 412

6x = 412 - 322

6x = 90

x = 15

Therefore there are 15 students in each van and 46 students in each bus.

3 0
2 years ago
Bronson builds a rectangular deck for his friend. the width of the deck is 29 feet. the perimeter of the deck must be at least 1
olga_2 [115]
<span>Answer: a) Greater than or equal to 38 feet b)Since there is no restriction on the perimeter there exists many possible values for the length of the deck. Explanation: Given that the width of the deck is 29 ft. and the perimeter of the deck is at least 134 ft. 134 = 2(length + width) 134 = (2 x length) + (2 x 29) 134 = (2 x length) + 58 2 x length = 134 - 58 2 x length = 76 length = 76 / 2 length = 38 ft Thus, the inequality will be: a)Length ≥ 38 ft b)since there is no restriction on the perimeter there exists many possible values for length of deck.</span>
4 0
3 years ago
Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
Zoey wants to use her computer tablet throughout a 6-hour flight. Upon takeoff, she uses the tablet for 2 hours and notices that
mojhsa [17]

6 hours Zoey can expect from the tablet on a full battery charge if the battery dropped by 33%, from 100% to 67%.

<h3>What is percentage?</h3>

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

Zoey wants to use her computer tablet throughout a 6-hour flight. Upon takeoff, she uses the tablet for 2 hours and notices that the battery dropped by 33%, from 100% to 67%.

Let's suppose x hours Zoey can expect from the tablet on a full battery charge.

The value of x can be calculated using:

x = (2×100)/33

x = 200/33

x = 6.06 ≈ 6 hours

Thus, 6 hours Zoey can expect from the tablet on a full battery charge if the battery dropped by 33%, from 100% to 67%.

Learn more about the percentage here:

brainly.com/question/8011401

#SPJ1

7 0
2 years ago
Which of the following statements are true? Select all that apply.
Tom [10]

Answer: The statements in options 2 and 4 are true.

Explanation:

The LCM of two numbers is the smallest number that is multiple of both numbers.

The factor of 8 and 12 are,

8=2\times 2\times 2

12=2\times 2\times 3

Since 2 and 2 are common in both but 2 and 3 are not same, therefore the L.C.M. of 8 and 12 is,

L.C.M.(8,12)=2\times 2\times 2\times 3=24

Therefore the statement in option 1 is incorrect.

The factor of 6 and 9 are,

6=2\times 3

9=3\times 3

Since 3 is common in both but 2 and 3 are not same, therefore the L.C.M. of 6 and 9 is,

L.C.M.(6,9)=2\times 3\times 3=18

Therefore the statement in option 2 is correct.

The factor of 11 and 4 are,

11=1\times 11

4=2\times 2

Since all factor are different, therefore the L.C.M. of 11 and 4 is,

L.C.M.(11,4)=1\times 11\times 2\times 2=44

Therefore the statement in option 3 is incorrect.

The factor of 9 and 10 are,

9=1\times 9

10=2\times 5

Since all factor are different, therefore the L.C.M. of 9 and 10 is,

L.C.M.(9,10)=1\times 9\times 2\times 5=90

Therefore the statement in option 4 is correct.

4 0
3 years ago
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