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3 years ago

5

If g (x)=2x + 1, find g (a + h)- g (a).

1 answer:

Amiraneli [1.4K]3 years ago

6 0

I hope this helps you

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The distance of a trip

Vladimir [108]

Answer:

T-.5 = x (200)

Step-by-step explanation:

Let T = total time in hours

30 mn = .5 hours 30 /60 = .5

$ 2.00 is the rate per hour.

so T − .5 = the time that will be charged at the rate

Therefore the total charge is then

T − .5 × 2.00

4 0

3 years ago

Solve the system of equation below x+y+z=2 x-y+5z=6

mamaluj [8]

X + y + z = 2
x - y + 5z = 6

cancelando +y com -y:

x + z = 2*(-5)
x + 5z = 6

-5x -5z = -10
...x +5z = 6
---------------------
-4x = -4 *(-1)
4x = 4
x = 4/4
x = 1

x + z = 2
1 + z = 2
z = 2 - 1
z = 1

x + y + z = 2
1 + y + 1 = 2
2 + y = 2
y = 2 - 2
y = 0

S: {x, y, z} = {1, 0, 1}

8 0

3 years ago

The answer and how you got the answer

olasank [31]

Answer:

$\frac{34}{15}$

Step-by-step explanation:

we are asked to evaluate

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

Above we are given mixed fraction which can be converted in proper fraction using formula given below

$a\tfrac{b}{c}=\frac{a \times c +b}{c}$

Hence

$4\tfrac{1}{4}=\frac{4 \times 4 +1}{4}$

$4\tfrac{1}{4}=\frac{17}{4}$

Also

$1\tfrac{7}{8}=\frac{1 \times 8 +7}{8}$

$1\tfrac{7}{8}=\frac{15}{8}$

Hence

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

can be written as

$\frac{17}{4}$ ÷ $\frac{15}{8}$

Also we know the rule for dividing fraction is as given below

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b} \times \frac{d}{c}$

Hence

$\frac{17}{4}$ ÷ $\frac{15}{8}$ = $\frac{17}{4} \times \frac{8}{15}$

= $\frac{17 \times 2}{15}$

= $\frac{34}{15}$

8 0

3 years ago

So this should be one of the last few ones

sergeinik [125]

Answer:

A

Step-by-step explanation:

Because you have to use the Pythagorean theorem to solve for this.

8 0

3 years ago

Finding Derivatives Implicity In Exercise, find dy/dx implicity.<br> 4x3 + ln y2 + 2y = 2x

lisov135 [29]

Answer:

$\frac{dy}{dx}=\frac{y(1-6x^2)}{(1+y)}$

Step-by-step explanation:

Given function : 4x³ + ln(y²) + 2y = 2x

on differentiating both sides with respect to 'x', we get

$\frac{d(4x^3 + ln(y^2) + 2y)}{dx}= \frac{d(2x)}{dx}$

or

$12x^2+\frac{2}{y}(\frac{dy}{dx})+2(\frac{dy}{dx})=2$

or

$12x^2+(\frac{2}{y}+2)\frac{dy}{dx}=2$

or

$(\frac{2+2y}{y})\frac{dy}{dx}=2-12x^2$

or

$\frac{dy}{dx}=\frac{y(2-12x^2)}{2+2y}$

or

$\frac{dy}{dx}=\frac{2y(1-6x^2)}{2(1+y)}$

or

$\frac{dy}{dx}=\frac{y(1-6x^2)}{(1+y)}$

3 0

3 years ago