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Dovator [93]
3 years ago
6

Please help me 3x+y=-3

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

x=0 y=-3

Step-by-step explanation:

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Reika [66]

Answer:

8

Step-by-step explanation:

5 0
2 years ago
5m<6m+6 pls help me ​
torisob [31]

Let's solve your inequality step-by-step.

5m<6m+6

Step 1: Subtract 6m from both sides.

5m−6m<6m+6−6m

−m<6

Step 2: Divide both sides by -1.

−m / −1 < 6 / −1

m>−6

Answer:

m>−6

4 0
3 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
3 years ago
Can someone please help me with these two questions ​
Anarel [89]

Answer:

  23.  0.4583 seconds

  24.  0.0107 seconds

Step-by-step explanation:

The problem statement tells you how to work it. You need to convert speed from miles per hour to feet (or inches) per second.

 90 mi/h = (90·5280 ft)/(3600 s) = 132 ft/s = (132·12 in)/s = 1584 in/s

__

23. The time it takes for the ball to travel 60.5 ft is ...

  time = distance/speed

  time = (60.5 ft)/(132 ft/s) = 0.4583 s

It takes 458.3 milliseconds to reach home plate.

__

24. time = distance/speed

  time = (17 in)/(1584 in/s) = 0.0107 s

The ball is in the strike zone for 10.7 milliseconds.

4 0
3 years ago
Which expression shows that the quotient
Harrizon [31]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

We further simplify this expression,

\frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

= \frac{2}{(3x-1)}\times \frac{6x-1}{6}

= \frac{6x-1}{3(3x-1)}

= \frac{6x-1}{(9x-3)}

Therefore, \frac{6x-1}{(9x-3)} will be the quotient of the given expression.

x\neq \frac{1}{3} and x\neq \frac{1}{6} for which the given expression is not defined.

Option (2) will be the answer.

6 0
3 years ago
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