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professor190 [17]
3 years ago
15

I need all the answers

Mathematics
2 answers:
vodomira [7]3 years ago
8 0
I don’t see the questions?!
olasank [31]3 years ago
3 0
Look in the back of the book
You might be interested in
Please, I need an answer to this question urgently.​
Blababa [14]

Answer:

156

Step-by-step explanation:

While solving we will have to use the area formula of the rectangle, which is :A=w*l ; length*width=A.

Steps:
1)let’s consider that the shape is a full rectangle. => 16*12=192.

2)9*2=18 -> 18*2=36

3)192-36=156.

4 0
3 years ago
Read 2 more answers
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Find the x-intercepts of the parabola with vertex (5,-4) and y-intercept (0,96). Write your answer in this form: (x1,y1),(x2,y2)
lesya692 [45]

Answer:

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

Step-by-step explanation:

we know that

The equation of the given parabola is

(y-k)=a(x-h)^{2}

we have

the vertex is the point (5,-4)

substitute

(y+4)=a(x-5)^{2}

The y-intercept is the point (0,96)

substitute and solve for a

(96+4)=a(0-5)^{2}

100=a(25)

a=100/25=4

The equation of the vertical parabola is equal to

(y+4)=4(x-5)^{2}

Find the x-intercepts

Remember that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

4=4(x-5)^{2}

Simplify

1=(x-5)^{2}

Rewrite

(x-5)^{2}=1

square root both sides

(x-5)=(+/-)1

x=(+/-)1+5

x=(+)1+5=6

x=(-)1+5=4

therefore

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

4 0
3 years ago
How is the number 2 in 582 similar to the 2 in the number 528
7nadin3 [17]
In the number 582, the 2 has a value of 2.
In the number 528, the 2 has a value of 20.

Similarities...
1) Both divisible by 2.
2) Both divisible by 1.
3) Both are even numbers.
4 0
3 years ago
Read 2 more answers
What is m 1.50°<br> 2. 35°<br> 3.130°<br> 4.95
Ann [662]

Answer:

∠ A = 50°

Step-by-step explanation:

The angle adjacent to 145° inside the triangle is

180° - 145° = 35°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

85° is an exterior angle of the triangle , then

∠ A + 35° = 85 ( subtract 35° from both sides )

∠ A = 50°

6 0
3 years ago
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