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algol13
3 years ago
5

Melissa reserves another rectangular patch in her vegetable garden for growing bell peppers. Since the space that she can reserv

e for a rectangular bell paper patch depends on how large she makes the tomato patch, she uses function p to represent the area of the bell pepper patch, where x is the length of the tomato patch.
1. Quadratic, linear, or exponential
2. 1.5,18,12,16
3. 20,12,16,18
4. 6,20,12,18

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:

Quadratic, 16, 18, 6

Step-by-step explanation:

Did this assignment myself

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Describe the steps required to determine the equation of a quadratic function given its zeros and a point.
faltersainse [42]

Answer:

Procedure:

1) Form a system of 3 linear equations based on the two zeroes and a point.

2) Solve the resulting system by analytical methods.

3) Substitute all coefficients.

Step-by-step explanation:

A quadratic function is a polynomial of the form:

y = a\cdot x^{2}+b\cdot x + c (1)

Where:

x - Independent variable.

y - Dependent variable.

a, b, c - Coefficients.

A value of x is a zero of the quadratic function if and only if y = 0. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: A(x,y) = (r_{1}, 0), B(x,y) = (r_{2},0) and C(x,y) = (x,y)

Based on such information, we form the following system of linear equations:

a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0 (2)

a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0 (3)

a\cdot x^{2} + b\cdot x + c = y (4)

There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }

a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }

b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }

c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

And finally we obtain the equation of the quadratic function given two zeroes and a point.

6 0
3 years ago
Determine if the statement is always, sometimes or never true. There are 300 degrees in the sum of the interior angles of a poly
Marrrta [24]

Answer:

Never

Step-by-step explanation:

Using the formula to find the sum of the interior angles, (n-2) * 180, we can work backwards.

300/180 +2 = 11/3 or 3.666. Polygons cannot have decimal sides therefore your answer is never.

6 0
3 years ago
Can someone help me. <br><br><br> Which equation represents the data in the table?
nydimaria [60]

Answer:

D) t=4d+5

Step-by-step explanation:

If d=1,

t=4\times 1+5\\t=9

If d=2,

t=4\times2+5\\=8+5\\=13

If d=4,

t=4\times4+5\\=16+5\\=21

Therefore,

t=4d+5

8 0
2 years ago
Read 2 more answers
One number is larger than another by 9. If the greater number is increased by 10, and the lesser number is tripled, the sum of t
kkurt [141]

Answer:

The larger number is -6, the smaller number is -15

Step-by-step explanation:

We have two numbers, a and b.

We know that one number is larger than another by 9.

Then we can write:

a = b + 9

then a is larger than b by 9 units.

If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:

(a + 10) + 3*b = -41

So we got two equations:

a = b + 9

(a + 10) + 3*b = -41

This is a system of equations.

One way to solve this is first isolate one variable in one of the two equations:

But we can see that the variable "a" is already isolated in the first equation, so we have:

a = b + 9

now we can replace that in the other equation:

(a + 10) + 3*b = -41

(b + 9) + 10 + 3*b = -41

now we can solve this for b.

9 + b + 10 + 3b = -41

(9 + 10) + (3b + b) = -41

19 + 4b = -41

4b = -41 -19 = -60

b = -60/4 = -15

b = -15

then:

a = b + 9

a = -15 + 9 = -6

a = -6

7 0
3 years ago
Thank you guys so much!!
Scilla [17]

Answer:

i think it's 6.5°C

hope this helps

8 0
3 years ago
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