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grigory [225]
2 years ago
8

If f(x) = -3x +4 and g(x) = 2, solve for the value of x for which f(x) = g(x) is true.

Mathematics
2 answers:
grin007 [14]2 years ago
5 0

Step-by-step explanation:

f(x) = g(x)

-3x + 4 = 2

4 - 2 = 3x

2/3 = x

Ghella [55]2 years ago
4 0

Answer:2/3

trust me just take your time and work it out and you will get the same 2/3

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A)<br> 2x + y - 12 = 0<br> x + y + 3 = 0
AVprozaik [17]

Answer:

x=15   and   y= -18

Step-by-step explanation:

2x + y - 12 = 0            Equation 1

x + y + 3 = 0                Equation 2

From two given equations, we can find the value of both x and y by finding the value of one variable from any one of the two equations in terms of other variable and putting it to other equation.

Solving equation 1

Finding 'y' in terms of 'x'           2x+y=12\\y=12-2x                 Equation 3

Putting above equation in equation 3 in 2

                                       x + y + 3 = 0

                                      x+12-2x+3=0

                                         x=15

Putting value of 'x' in equation 3 to find the value of 'y'

                                      y=12-2(15)\\y=12-30\\y= -18

6 0
3 years ago
Can so.eone explain to me by what bisecting intervals are?​
Tasya [4]

When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)

Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:

• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]

• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]

• bisecting an arbitrary interval [a,b] gives the intervals \left[a,\frac{a+b}2\right] and \left[\frac{a+b}2,b\right]

7 0
2 years ago
Factoring the expression 15x+6 using GCF
s344n2d4d5 [400]
The answer is 3(5x+2) i hope this helps you.
3 0
2 years ago
Please answer below thx.
slava [35]

Answer:

24 cm

Step-by-step explanation:

since the two triangles are similar,

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8 0
3 years ago
A manufacturer is designing a flashlight. For the flashlight to emit a focused beam, the bulb needs to be on the central axis of
aalyn [17]
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
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So, we form the equation
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To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12

Source:
http://www.1728.org/quadr4.htm




5 0
3 years ago
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