Answer:
x=15 and y= -18
Step-by-step explanation:
Equation 1
Equation 2
From two given equations, we can find the value of both x and y by finding the value of one variable from any one of the two equations in terms of other variable and putting it to other equation.
Solving equation 1
Finding 'y' in terms of 'x'
Equation 3
Putting above equation in equation 3 in 2



Putting value of 'x' in equation 3 to find the value of 'y'

When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)
Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:
• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]
• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]
• bisecting an arbitrary interval
gives the intervals
and ![\left[\frac{a+b}2,b\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Ba%2Bb%7D2%2Cb%5Cright%5D)
The answer is 3(5x+2) i hope this helps you.
Answer:
24 cm
Step-by-step explanation:
since the two triangles are similar,
10cm/20cm = 36cm _ h/h
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm