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S_A_V [24]
3 years ago
14

Write the sum using summation notation, assuming the suggested pattern continues.

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

\sum_{n=5}^{\infty}n^2

Step-by-step explanation:

The pattern given is:

25+36+49+64+...+n^2+...

The pattern can be written as

(5)^2+(6)^2+(7)^2+(8)^2+.....+n^2+....

The series is started with 5 and it continues up to infinity.

The summation notation for the given series is:

\sum_{n=5}^{\infty} n^2

n= 1 and goes up to infinity and the series is made up of taking square of n,

Levart [38]3 years ago
3 0
<h2>Answer:</h2>

The sum using summation notation, assuming the suggested pattern continues is :

     25 + 36 + 49 + 64 + ... + n^2 + ...=\sum_{n=5}^{\infty} n^2      

<h2>Step-by-step explanation:</h2>

We are given a series of numbers as

          25 + 36 + 49 + 64 + ... + n^2 + ...

To write the sum using summation notation means we need to express this series in terms of a general n such that there is a whole summation expressing this series.

Here we see that each of the numbers could be expressed as follows:

25=5^2\\\\36=6^2\\\\49=7^2\\\\64=8^2

and so on.

i.e. the series starts by taking the square of 5 then of 6 then 7 and so on.

and the series goes to infinity.

Hence, the summation notation will be given by:

25 + 36 + 49 + 64 + ... + n^2 + ...=\sum_{n=5}^{\infty} n^2

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DedPeter [7]

Answer:

The correct option is  2 .

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Step-by-step explanation:

For a Quadratic Equation ax² + bx + c = 0

By Formula Method we get

x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

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On Comparing we get

a=2\\b=-8\\c=7

Substituting a , b, c values we get

x=\dfrac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(7)}}{2(2)}\\\\x=\dfrac{8\pm\sqrt{64-56}}{4}\\\\x=\dfrac{8\pm\sqrt{8}}{4}\\\\x=\dfrac{8\pm2\sqrt{2}}{4}\\\\x=2(\dfrac{4\pm\sqrt{2}}{4})\\\\x=\dfrac{4\pm\sqrt{2}}{2}

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7 0
3 years ago
What is the answer / product of 8x2
Mademuasel [1]

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    8*x^2-(8)=0  

Step by step solution :

STEP

1

:

Equation at the end of step 1

 23x2 -  8  = 0  

STEP

2

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STEP

3

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Pulling out like terms

3.1     Pull out like factors :

  8x2 - 8  =   8 • (x2 - 1)  

Trying to factor as a Difference of Squares:

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Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check :  x2  is the square of  x1  

Factorization is :       (x + 1)  •  (x - 1)  

Equation at the end of step

3

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STEP

4

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Equations which are never true:

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This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

4.3      Solve  :    x+1 = 0  

Subtract  1  from both sides of the equation :  

                     x = -1

Solving a Single Variable Equation:

4.4      Solve  :    x-1 = 0  

Add  1  to both sides of the equation :  

                     x = 1

Two solutions were found :

x = 1

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Ne4ueva [31]
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