Answer: D
Step-by-step explanation:
It seems there is two ways to solve this, remember that this is just one of them.
The triangle to the left is an isosceles triangle by definition. It is given that two of its sides are equal.
The angles opposite the equal sides in an isosceles triangle are congruent. It is given that one of these angles is 70 degrees, so the other one must be 70 degrees as well.
This angle is opposite to Angle Y. Vertical angles are congruent, so Angle Y must be 70 degrees.
D is the answer.
The greatest common factor (GCF) of 48 and 78 is: 6
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Factors of 78: 1, 2, 3, 6, 13, 26, 39
The common factors between the two numbers are 1, 2, 3, and 6, but considering 6 is the highest number out of them, it is the greatest common factor.
To divide fractions:
Flip the second fraction
Multiply the numerators
Multiply the denominators
Simplify
2/9*10/9
2*10=20
9*9=81
20/81
Hope this helps!!
Answer:
Beyonce will get the same result.
Step-by-step explanation:
The given system is
2x-3y=-2
and 4
x+y=24
This system contains two lines that are not parallel to each other therefore the solution x=5, y=4 is unique.
It doesn't matter which method he used or which variable he eliminated first.
The solution will still be the same.
If the system of two equations with has no solution, the Beyonce will not get a solution in the first place, but the fact that the system has no solution remains the same even if Beyonce uses a different method.
If there are infinite solutions, Beyonce might get different solutions using a different method, but the fact that the system has infinite solution remains the same.
Answer : (1,-1)
a line through the points (-1, 1), (0, 2), (1, 3)
To find the point in the graph of inverse function we interchange x and y values
For point (-1 , 1) , the point on inverse function is (1, -1)
For point (0 , 2) , the point on inverse function is (2, 0)
For point (1 , 3) , the point on inverse function is (3, 1)
so (1,-1) will be included in the graph of the inverse of the function
