I’m pretty sure the answer is B.
Answer:
2sin(2x)-2sinx+2sqrt3cosx-sqrt3 = 0
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4sin(x)cos(x) - 2sin(x) + 2sqrt(3)cos(x) - sqrt(3) = 0
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Factor:
2sin(x)[2cos(x)-1] + sqrt(3)[2cos(x)-1] = 0
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[2cos(x)-1][2sin(x)+sqrt(3)] = 0
Solve:
2cos(x)-1 = 0 or 2sin(x)+sqrt(3) = 0
cos(x) = 1/2 or sin(x) = -sqrt(3)/2
x = +/-pi/3 or x = -pi/3 or (4/3)pi
hope this helps!
Answer:
2nd option
Step-by-step explanation:
using the converse of Pyhagoras' identity
If the square of the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.
longest side = 100 , then 100² = 10000
60² + 80² = 3600 + 6400 = 10000
then
60² + 80² = 100²
thus the triangle is right
Simplified: 6x^3- 30x^2+3x
Hope this is helpful. :)
