The first term is a₁ = 2.
Each subsequent term is the reciprocal of the square of the preceding term.
2nd term:
a₂ = 1/2² = 1/4
3rd term:
a₃ = 1/(1/4)² = 1/(1/16) = 16
4th term:
a₄ = 1/16² = 1/256
5th term:
a₅ = 1/(1/256)² = 1/(1/65536) = 65536
The positive square root of the fifth term is
√(65536) = 256
Answer: 256
Triangles PQR and PSR are right triangles, with both QR = SR = 5 (since these are radii of the circle R).
TR is also a radius of the circle, so TR = 5, making PR = 4 + TR = 9.
Because PQR and PSR are right triangles, we can compute the length of the missing side, which will be equal. By the Pythagorean theorem,
PQ^2 + QR^2 = PR^2
PQ^2 + 5^2 = 9^2
PQ^2 = 56
PQ = √56 = 2√14
Then the perimeter of PQRS is
PQ + QR + RS + SP = 2√14 + 5 + 5 + 2√14 = 10 + 4√14
and so the answer is B.
<h3>Given :</h3>
<h3>To Find :</h3>
<h3>Solution :</h3>
By taking L common from 
, we get :
Hence, value of 
Answer:
110
Step-by-step explanation:
10% of 100 is 10
100+10=110
