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3 years ago

it took Simon 33 minutes to run 5.5 miles. did he run faster or slower than 1 mile every 5 minutes how can you tell

Mathematics

1 answer:

vitfil [10]3 years ago

4 0

Simon ran slower than 1 mile every 5 minutes.

Because 33 / 5.5 = 6. So he ran 1 mile every 6 minutes, not 5.

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The following data on average daily hotel room rate and amount spent on entertainment (The Wall Street Journal, August 18, 2011)

Zielflug [23.3K]

Answer:

a. Predicted Amount = $109.46

b. Confidence Interval = (94.84,124.08)

c. Interval = (110.6883,188.8517)

Step-by-step explanation:

Given

ŷ = 17.49 + 1.0334x.

SSE = 1541.4

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46 --- Approximated

Predicted Amount = $109.46

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46

First we calculate the standard deviation

variance = SSE/(n-2)

v = 1541.4/(9-2)

v = 1541.4/7

v = 220.2

s = √v

s = √220.2

s = 14.839

Then we calculate mean(x) and ∑(x - (mean(x))²

X --- Y -- Mean(x) --- ∑(x - (mean(x))²

148 -- 161 -- 43-- 1849

96 || 105|| -9 || 81

91 ||101 || -14 || 196

110 || 142 || 5 || 25

90 || 100 || -15 || 225

102 || ||120 ||-3|| 9

136 || 167 ||31 ||961

90 || 140 ||-15 ||225

82 || 98 ||-23 || 529

Sum 945 || 1134|| 0 ||4100

Mean (x) = 945/9 = 105

∑(x - (mean(x))² = 4100

α = 1 - 95% = 5%

α/2 = 2.5% = 0.025

tα,df = n − 2 = t0.025,7 =2.365

Confidence interval = 109.46 ± 2.365 * 14.839 √((1/9)+ (89-105)²/4100

Confidence Interval = (109.46 ± 14.62)

Confidence Interval = (94.84,124.08)

ŷ = 17.49 + 1.0334(128)

ŷ = 149.7652

ŷ = 149.77

Interval = 149.77 ± 2.365 * 14.839 √((1/9)+ (128-105)²/4100

Interval = 149.77 ± 39.0817

Interval = (110.6883,188.8517)

3 0

3 years ago

Please I need Help!!! I need someone to help me do markdown's!!!

marta [7]

Answer:

The retail price is $103.6

Step-by-step explanation:

Markdowns are, to be simple, when the price goes DOWN, so the price would be less than the original rather than more. First, you must calculate what one percent of the original is, which is 1.40. As the markdown is 26 percent, you can do 1.40 x 26 to get how much was marked down, which is $36.40. To find the new price now, you must do the original minus the markdown, or 140 - 36.40 in this case. This gives you $103.6 as the retail price.

I hope this helped! :D

7 0

2 years ago

Find the domain and range X+ | X |

Lesechka [4]

9514 1404 393

Answer:

domain: all real numbers, (-∞, ∞)
range: all non-negative numbers, [0, ∞)

Step-by-step explanation:

There are no values of x for which this expression is undefined. The domain is all real numbers.

The minimum value of this expression is 0. There is no maximum value. The range is all numbers greater than or equal to zero.

4 0

3 years ago

A motorist drives for m hours at 120km/hr and n hours at 18km/hr. Altogether Somina drives 78km in 5 hours. Find m and n.

nikdorinn [45]

Answer:

(0.118, 4.882)

Step-by-step explanation:

If a motorist drives for m hours at 120km/hr, then the Distance of the motorist is expressed as;

Distance = Speed * time

da = 120m

If he drives n hours at 18km/hr;

db = 18 * n

db = 18n

Speed of the motorist altogether is expressed as;

Speed =78km/5hrs

Speed = 15.6km/hr

SInce the total distnce is 78km

120m + 18n = 78 ....1 ..... * 1

If total time is 5hrs

m + n = 5....2 ...*18

Solve simultaneously

120m + 18n = 78

18m + 18n = 90

Subtract

120m - 18m = 78-90

102m = -12

m = 0.118 hrs

m =

Since m + n = 5

n = 5 - m

= 5 - 12/102

n = 4.882

Hence (m,n) is (0.118, 4.882)

3 0

3 years ago

Solve w=x/y-x for x.

lesya [120]

Answer:

Rewrite the equation as x+xyz=wx+xyz=w.

x+xyz=wx+xyz=w

Subtract xx from both sides of the equation.

xyz=w−xxyz=w-x

Divide each term by xzxz and simplif

5 0

2 years ago

it took Simon 33 minutes to run 5.5 miles. did he run faster or slower than 1 mile every 5 minutes how can you tell ​

it took Simon 33 minutes to run 5.5 miles. did he run faster or slower than 1 mile every 5 minutes how can you tell