Gabriella is three years younger than her sister, Amy. If

Mathematics

2 answers:

seraphim [82]2 years ago

7 0

Answer:

Amy is 8 years old.

Step-by-step explanation:

5 + 3 = 8

If Gabriella is three years younger then Amy then all you have to do is add 5 (Gabriella's age) plus 3 (how much older Amy is than Gabriella) and that is 8.

NemiM [27]2 years ago

6 0

Answer:

5+3 is Amy, so Amy is 8

Step-by-step explanation:

So, lets say amy is a

and gabriella is g

WE know that g=5, because gabriella is 5 years old

And, Gabriells is younger than Amy, so we need to add to get Amy's age

So, 5 ( Gabriella's age ) + 3=Amy

So, 5+3= Amy

So Amy is 8

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How to solve this question

Viefleur [7K]

Answer:

7x+21 = 7x + 21

Step-by-step explanation:

7(x+3)=6-(-7x - 15)

L.H.S

=7(x+3)

=7x+21 (multiply 7 by (x+3))

R.H.S:

=6-(-7x - 15)

= 6+7x+15 (multiply the -ive sign in the bracket)

= 7x + 21 ( adding 15 and 6)

now compare the two sides

7x+21 = 7x + 21 hence we prove that L.H.S= R.H.S

4 0

2 years ago

RSB [31]

Answer:

Step-by-step explanation:

3x² - 3x + 7 = 0

a = 3 ; b = -3 and c = 7

D = b² - 4ac = (-3)² - 4*3*7

D = 9 - 84 = - 75

D = 75i²

√D = √75i² = $\sqrt{5*5*3 * i * i}= 5i\sqrt{3}$

$x = \dfrac{-b+\sqrt{D}}{2a} \ ; \ x=\dfrac{-b-\sqrt{D}}{2a}\\\\ \\x=\dfrac{3+5i\sqrt{3}}{6} ; \ ; x = \dfrac{3-5i\sqrt{3}}{6}\\\\\\x =\dfrac{3}{6}+\dfrac{5i\sqrt{3}}{6} ; \ ; x=\dfrac{3}{6}-\dfrac{5i\sqrt{3}}{6}\\\\\\Solution:\\\\x=\dfrac{1}{2}+\dfrac{5\sqrt{3}}{6}i ; \ ; x=\dfrac{1}{2}-\dfrac{5\sqrt{3}}{6}i$