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Natali5045456 [20]
3 years ago
6

Quincy found 120 shells during four days at the beach. if quincy found the same number of shells each day, how many shells did h

e find each day?
Mathematics
2 answers:
Svetach [21]3 years ago
5 0
If Quincy finds 120 shells in 4 days, we can use the equation 4x = 120 to find how many shells she found each day. 4x = 120 If we divide both sides by four we get x = 30 So Quincy found 30 shells each day.
shutvik [7]3 years ago
3 0
120 shells over 4 days
120/4 gives shells per day
30 shells per day.
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Two legs of a right triangle are 4cm, and 3cm. find the length of the hypotenuse of this triangle
sergiy2304 [10]
It'll be 4^2+ 3^2 then the answer you get you take the square root of it which will give you the hypotenuse.
Your answer would be 5 because square root of 25 is 5
If u want the formula it's a^2+b^=c^2
C is the hypotenuse and a and b is the lengths
6 0
3 years ago
A circle of yellow tulips is planted in Cedarburg's central park. Pam measured the circle and calculated that is has a circumfer
lozanna [386]

Answer:

The circle's diameter is 4\ yd

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=\pi D

where

D is the diameter of the circle

In this problem we have

C=12.56\ yd

\pi=3.14

substitute the values and solve for D

12.56=(3.14)D

D=12.56/(3.14)=4\ yd

6 0
3 years ago
An independent research firm conducted a study of 100 randomly selected children who were participating in a program advertised
kap26 [50]

Answer:

b) use a two-sided test instead of a one sided test.

Step-by-step explanation:

If we are using a significance level of 0.05, then the two-tailed test assigns half alpha to test for statistical significance in one direction and half alpha to test statistical significance in the other direction. This implies that .025 is present in each tail of the test statistical distribution. When using the two-tailed test, regardless of the direction of the relationship you assume, we test the possibility of the relationship in both directions.

7 0
3 years ago
SOMEONE PLEASE HELP<br> find the greatest common factor <br> 14g5h2, 56g3h4, 77g3h2
andrezito [222]

Answer:

\large\boxed{GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=g^3h^2}

Step-by-step explanation:

14g^5h^2=2\cdot7\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot g\cdot g\cdot \boxed{h}\cdot \boxed{h}\\\\56g^3h^4=2\cdot2\cdot2\cdot7\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\cdot h\cdot h\\\\77g^3h^2=7\cdot11\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\\\\GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}=g^3h^2

8 0
3 years ago
A research scientist wants to know how many times per hour a certain strand of bacteria reproduces. The mean is found to be 13.6
dimaraw [331]

Answer:

The confidence interval is  13.4<  \mu < 13.8

Step-by-step explanation:

From the question we are told that

   The sample  mean is \= x  =  13.6

     The standard deviation is \sigma =  1.9

     The sample  size is  n  =  189

given that the confidence level is  85% then the level of significance is mathematically represented as

            \alpha = (100 - 85 )\%

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Next we obtain the critical value  of \frac{\alpha }{2} from the normal distribution table  the value  is  

      Z_{\frac{\alpha }{2} } =  1.44

Generally the margin of error is mathematically represented as

        E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>     E = 1.44*  \frac{1.9}{\sqrt{189} }

=>     E = 0.1990

The  85%  confidence interval is mathematically represented as  

        \= x  - E <  \mu

=>      13.6- 0.1990 <  \mu <  13.6+ 0.1990

=>      13.4<  \mu < 13.8

           

5 0
3 years ago
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