Use the information provided to write the equation of the circle Center: (10,-9) Point on Circle: (12,-13)

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

7 0

Answer:

(x - 10)² + (y + 9)² = 20

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

The radius is the distance from the centre to a point on the circle

To calculate r use the distance formula

r = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (10, - 9) and (x₂, y₂ ) = (12, - 13)

r = $\sqrt{(12-10)^2+(-13+9)^2}$

= $\sqrt{4+16}$ = $\sqrt{20}$ , hence

(x - 10)² + (y - (- 9))² = ( $\sqrt{20}$ )², that is

(x - 10)² + (y + 9)² = 20

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Austin uses 435.714 milliliters of solution B to get a resulting mixture that has 244 milliliters of pure alcohol.

Step-by-step explanation:

Step 1; Assume solution B has 1x ml of liquid in it. As solution A has three times that of solution B, it has 3x ml of liquid.

Step 2; In solution A there is 12% of alcohol and solution B has 20% alcohol. So alcohol content in solution A is 12% of 3x = 0.12 x 3x and the alcohol content in solution B is 20% of x= 0.20 x 1x.

Step 3; Use this formula

$Concentration percent= \frac{(volume of solute)}{(volume of solution)} * 100$

here Volume of solute is the total of solution A and B= (0.12 x 3x) + (0.20 x 1x) which equals 0.56x. The volume of solution is 3x + 1x which equals 4x. Substituting numerator and denominators we get a volume of 14%.

Step 4;This 14% is the concentration of alcohol in the mixture of solution A and solution B which is given as 244 ml. If 14% is 244 ml then 100% equals 1742.857 milliliters. The total of solution A and B equal 4x which is 1742.857 milliliters. So we get solution A has 1307.1428 milliliters and solution B has 435.71428 milliliters of liquid.

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3 years ago

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blsea [12.9K]

Check the picture below.

now, notice the triangles made, 3 right triangles with legs of 5 and 4 each.

looking at quadrilateral (1), from the leg 5 units long, we have a line with a run of -1 and a rise of 3, from the leg 4 units long, we have a line with a run of 4 and a rise of -1.

Now, quadrilaterals (2) and (4) display the same lengths and rise and runs, which means they're all congruent, quadrilateral (3) has no equal.

so 1 ≅ 2 and 1 ≅ 4.