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3 years ago

12

Sarah married 8 times ,the first marriage her husband cheated leaving her with 2 children,her second husband died leaving her wi

th three children ,all her other marriages ended in disaster leaving her with one more than the last .How many children does Sarah have all together.

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

probably 6 or 11 not too sure but that's my answer

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Answer:

A

Step-by-step explanation:

Solving for 1995, which is 5 years after 1990, so plug in 5 as t.

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n= 18.4

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3 years ago

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Answer:

$ 8,695.35

Step-by-step explanation:

This is a compound interest question

Amount after t years = A = P(1 + r/n)^nt

Where P = Initial Amount saved

r = interest rate

t = time in years

n = compounding frequency

A = 10,000

r = 3.5 %

t = 21 - 17 = 4 years

n = Compounded monthly = 12

Step 1

Converting R percent to r a decimal

r = R/100 = 3.5%/100 = 0.035 per year.

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3 years ago

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Brian has $776 more account in his account than Chris.

Step-by-step explanation:

Compound interest Formula:

$A=P(1+r)^t$

$I$ = A-P

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r= Rate of interest

t= Time in year

Given that,

Brian invests $10,000 in an account earning 4% interest, compounded annually for 10 years.

Here P = $10,000 , r= 4%=0.04, t=10 years

The amount in his account after 10 years is

$A=10000(1+0.04)^{10}$

=$14802.44

≈$14802

Five years after Brian's investment,Chris invests $10,000 in an account earning 7% interest, compounded annually for 5 years.

Here P = $10,000 , r= 7%=0.07, t=5 years

The amount in his account after 5 years is

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