Answer:
The average value of over the interval is .
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval by algebraic handling:
The average value of over the interval is .
Answer:
The answer is B.
Step-by-step explanation:
Diameter x Pi = Circumference
8 x 3.14 = 25.12
Answer:
d. 6
Step-by-step explanation: