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rusak2 [61]
3 years ago
6

I need to know this asap

Mathematics
2 answers:
MrMuchimi3 years ago
7 0
-17                        17
-----     -(-17)         ----
  8          ----          -8
                8
just olya [345]3 years ago
3 0
-17/8
-(-17/-8)
17/-8
an odd number of negative yields a negative!
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The supplement of an angle measures 102°. what is the measurement of the angle?
Evgen [1.6K]
   
180° - 102° = 78°
Correct answer:   a.  



3 0
3 years ago
Five times a number plus 5 has the same value as twice the number plus 10
NemiM [27]

Answer: x=5/3

Step-by-step explanation:

For this problem, we can use teh information given to write out an equation and solve. Let's use x for the unknown number.

5x+5=2x+10

The left side of the equation comes from the part that says "five times a number plus 5". That is modeled above. The right side of the equation comes from "has the same value as twice the number plus 10".

5x+5=2x+10                     [subtract both sides by 2x]

3x+5=10                           [subtract both sides by 5]

3x=5                                [divide both sides by 3]

x=5/3

Now, we have found the unknown number, x=5/3.

6 0
3 years ago
Consider the function represented by the table. For which x is f(x)?=–3 –7 –4 4 5
svp [43]
-7. When you look at the graph it is divided into x and f(x). f(x) is the same as y so the question is basically asking you what is x when y is -3. So you just go to the -3 under f(x) and look over to find that the answer is -7
7 0
3 years ago
Read 2 more answers
If x= 1/2-√3 , prove that x³-2x²-7x+5=3
prohojiy [21]
x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5

=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3
6 0
3 years ago
2n+5=20?????????????
Oksanka [162]

2n+5=20

Subtract 5 from 5 and 20

2n=15

Divide 15 and 2 by 2

n=7.5

:P

8 0
3 years ago
Read 2 more answers
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