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2 years ago

PLEASE HELP PLEASE PLEASE DUE TONIGHT I HAVE NO IDEA HOW TO DO THIS

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

4 0

Answer:

I feel bad for you I really would like to help you but I haven't even learn that stuff yet

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Solve the equation x2 + 7x = 30.

Law Incorporation [45]

Answer:

2*7=14+6=30 points plz

5 0

2 years ago

i When 20 is added to a certain number and the sun is divided by 3, the result is 3 times the number, find the number.

Bingel [31]

Answer:

$let \: the \: number \: be \: x \\ \frac{20 + x}{3} = 3x \\ \frac{3(20 + x)}{3} = (3x)3 \\ 20 + x = 9x \\ 20 = 9x - x \\ 20 = 8x \\ \frac{20}{8} = \frac{8x}{8} \\ x = 2.5$

Step-by-step explanation:

Hope that this is helpful .

Have a great day.

3 0

2 years ago

Classify the triangle.<br> obtuse<br> equiangular<br> right<br> acute

CaHeK987 [17]

Answer:

acute triangle

Step-by-step explanation:

We have 3 angles that are not equal to each other

They are all smaller than 90 degrees which means they are acute angles

3 0

2 years ago

Read 2 more answers

The elevation of city a is 80 feet below sea level, the elevation of city c is 16 feet below sea level. The elevation of city D

tekilochka [14]

I am almost positive that the answer could be 8 feet below sea level

6 0

2 years ago

WILL MARK BRAINLIEST!

Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle $\Delta XYZ$ stretched through the factor "2".

$m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\$

right triangles:

$\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\$

complementary angles:

$\angle X \ and\ \angle Z$

$m\angle Z = 90^{\circ} - m\angle X \\\\$

complementary angles:

$\angle A \ and\ \angle B$

$m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\$

Same triangles: proportional side are corresponding, congruence angles are respective.

$\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\ \Delta XYZ\\\\$

Calculating the length of leg XY:

$XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\$

3 0

2 years ago