Find the product. x3(x2+5x+1)

I think I got this for the most part just need to be surs

defon

Answer:

a) 37.33 tons

b) 96 tons

c) Week 2

Step-by-step explanation:

a) 40+40+32=112÷3=37.33 tons

b) 32+40+24=96 tons

c) Week 2

6 0

3 years ago

Find the surface area of the pyramid. 64in^2 56in^2 88in^2 118in^2

ziro4ka [17]

Answer:

To find the surface area of this pyramid, we must find the area of one triangle flap which we then multiply by 4 because there are 4 of those equal triangle flaps surrounding the base(square). Once we find the area of those triangles, we then find the base(square)'s area. Next, we add all those areas together to get the result of the surface area.

Formula for area of triangle;

A = BH x 1/2

Where 'B' represents the base, 'H' represents the height, and 1/2 is just dividing the product of those two lengths by 2.

Plug in what you know, given that the base of one triangle is 4, and the height is 6.

A = 4(6) x 1/2

A = 24 x 1/2

A = 24/2

A = 12, the area of one triangle is 12 inches.

Now, we find the area of all the triangles by multiplying the area of one triangle by 4.

12 = Area of triangle

4 triangles in total, so:

12(4)

= 48 inches is the area of all the triangles.

Now we find the area of the base(square) using the formula;

(vol of square formula)
A = $s^{2}$

Where 's' represents one side of the square which is being squared.

or

A = l · w

Where 'l' represents the length and 'w' represents the width.

Plug in what you know, given that one side of the square is 4 inches (as well as the length and width).

(I'll be using the formula $s^{2}$ )

A = $s^{2}$

A = 4^2 ← (The symbol ' ^ ' means raised to the power of.)

A = 16, the area of the base(square) is 16 inches.

Now we add both areas together:-

48 + 16

= 64 inches^2 is the surface area, your answer is A.

5 0

2 years ago

Jessie finish the first race in two minutes and seven seconds 10 finish 12 seconds faster than Jesse one finished eight seconds

Mandarinka [93]

20 seconds faster than Jesse so one minute and 57 seconds is my best guess.

3 0

3 years ago

Graph for f(x)=6^6 and f(x)=14^x

zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0

3 years ago

A bird catches a fish flies 100 yards upward in a straight line and then drops the fish the fish Atlanta at a spot that is 50 ya

labwork [276]

Cos(x) = 50/100

part a) x= 60°
part b) height is 86.60254040

4 0

4 years ago