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Lina20 [59]
4 years ago
13

For the following exercises, find a formula for an exponential function that passes through the two points given. (0,6) and (3,7

50)
Mathematics
1 answer:
kirill [66]4 years ago
5 0

\boxed{\boxed{f(x)=6(5)^x}}

<h2>Explanation:</h2>

An exponential function is given by the following form:

y=ab^x \\ \\ Where: \\ \\ a \ is \ a \ constant \ and \ b \ is \ the \ base

Here we know two points:

(0,6) \ and \ (3,750)

\bullet \ (0,6) \\ \\ x=0, \ y=6 \\ \\ 6=ab^0 \\ \\ \boxed{a=6} \\ \\\ \\ \bullet \ (3,750) \\ \\ x=3, \ y=750 \\ \\ 750=6b^3 \\ \\ b^3=\frac{750}{6} \\ \\ b=\sqrt[3]{125} \\ \\ \boxed{b=5}

Finally, our exponential function is:

\boxed{\boxed{f(x)=6(5)^x}}

<h2>Learn more:</h2>

Behavior of functions: brainly.com/question/12891789

#LearnWithBrainly

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Find the zeros of the following function. List both in the blank below.<br> f(x) = x^2- 2x-15
Elza [17]

Answer:

x=5, -3

Step-by-step explanation:

To find the roots, replace y with 0 and solve for x. Hope this helps!

3 0
3 years ago
Secant jkl and jmn are drawn to circle o from an external point ,j. if jk=8,lk=4 and jm=6 what is the length of jn answer
Archy [21]
See the picture attached to better understand the problem

we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm

we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12

jn=jl*jk/jm-----> jn=12*8/6----> jn=16

the answer is
jn=16

6 0
4 years ago
For each equation, determine whether it has no solutions, exactly one solution, or is true for all values of x (and has infinite
nignag [31]

Answer:

  • Equation 1 has exactly one solution.
  • Equation 2 has infinitely many solutions.
  • Equation 3 has no solution.

Step-by-step explanation:

We are given three equations to solve. First, let's solve the equations for x.

<u>Equation 1</u>

<u />\displaystyle{6x+8=7x+13}\\\\7x + 13 = 6x + 8\\\\x + 13 = 8\\\\\bold{x = -5}<u />

Therefore, we determined that for the first equation, x = -5. We can check our solution by substituting it back into the original equation.

\displaystyle{6(-5)+8=7(-5)+13}\\\\-30 + 8 = -35 + 13\\\\-22 = -22 \ \checkmark

Since we got a true statement, there are no other values of x for which we get a true statement. Let's test this with the opposite value: positive 5.

6(5)+8=7(5)+13\\\\30 + 8 = 35 + 13\\\\38 = 48 \ \text{X}

Therefore, for Equation 1, there is exactly one solution.

<u>Equation 2</u>

<u />6 x + 8 = 2 ( 3 x + 4 )\\\\6x + 8 = 6x + 8\\\\0 + 8 = 8\\\\8 = 8 \ \checkmark<u />

We get a true statement by solving for x (which ends up canceling out of the equation entirely). Therefore, we can check <u>any value</u> in place of x to see if we get a true statement. For this instance, I will use -3.

6(-3) + 8 = 2 ( 3(-3) + 4 )\\\\-18 + 8 = 2(-9+4)\\\\-18 + 8 = 2(-5)\\\\-18 + 8 = -10\\\\-18 = -18 \ \checkmark

We still get a true statement, so Equation 2 has infinitely many solutions.

<u>Equation 3</u>

<u />6 x + 8 = 6 x + 13\\\\0 + 8 = 13\\\\8 \neq 13<u />

We get a false statement. Therefore, Equation 3 has no solution.

3 0
3 years ago
Read 2 more answers
A. 12
kondor19780726 [428]

Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The  student is 6 feet tall. What is the height of the tree? Show all work

<em><u>Answer:</u></em>

Option D

The height of tree is 20 feet tall

<em><u>Solution:</u></em>

From given question,

Shadow of tree = 30 feet

Height of tree = ?

Height of student = 6 feet

Shadow of student = 9 feet

We have to find the height of tree

We can solve the sum by proportion

\frac{\text{height of tree}}{\text{shadow of tree}} = \frac{\text{height of student}}{\text{shadow of tree}}

This forms a proportion and we can solve the sum by cross multiplying

\frac{\text{height of tree}}{30} = \frac{6}{9}\\\\\text{height of tree} = 30 \times \frac{6}{9} = 30 \times \frac{2}{3}\\\\\text{ height of tree } = 10 \times 2 = 20

Thus height of tree is 20 feet tall

5 0
3 years ago
To turn 2⁄5 into a decimal, what operation must you perform?
natali 33 [55]
D. 2 ÷ 5.......................
4 0
3 years ago
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