Find the percentage of data points that lie between -3.01 and 2.61? z= (x-u) /o
1 answer:
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Ok, a fun hack
if f⁻¹(a)=b then f(b)=a
so if f⁻¹(7)=b then f(b)=7
to find b, find x such that f(x)=7
7=0.5(3)^x
times both sides by 2 (or divide both sides by 0.5)
14=3^x
take log₃ of both sides
if f⁻¹(a)=b then f(b)=a
so if f⁻¹(7)=b then f(b)=7
to find b, find x such that f(x)=7
7=0.5(3)^x
times both sides by 2 (or divide both sides by 0.5)
14=3^x
take log₃ of both sides
The formula would be:
<span>y = mx + b
</span><span>
Now, let's look at the information we know.
m = slope
b = y-intercept
y-intercept = -6
x-intercept = -2
</span>
First, we would need to determine the slope. The formula for slope is m =
Plug your coordinates in and solve it.
= 6/-2 = -3
Now, since we have the slope and y-intercept, we are ready to plug them into the formula.
y = -3x - 6
I hope this helps!
<span>y = mx + b
</span><span>
Now, let's look at the information we know.
m = slope
b = y-intercept
y-intercept = -6
x-intercept = -2
</span>
First, we would need to determine the slope. The formula for slope is m =
Plug your coordinates in and solve it.
Now, since we have the slope and y-intercept, we are ready to plug them into the formula.
y = -3x - 6
I hope this helps!
Answer:
Given :- ABCD is a square.
To proof :- AC = BD and AC ⊥ BD
Proof :- In △ ADB and △ BCA
AD = BC [ Sides of a square are equal ]
∠BAD = ∠ABC [ 90° each ]
AB = BA [ Common side ]
△ADB ≅ △BCA [ SAS congruency rule ]
⇒ AC = BD [ Corresponding parts of congruent triangles are equal ]
In △AOB and △AOD
OB = OD [ Square is also a parallelogram therefore, diagonal of parallelogram bisect each other ]
AB = AD [ Sides of a square are equal ]
AO = AO [ Common side ]
△AOB ≅ △ AOD [ SSS congruency rule ]
⇒ ∠AOB = ∠AOD [ Corresponding parts of congruent triangles are equal]
∠AOB + ∠AOD = 180° [ Linear pair ]
∠ AOB = ∠AOD = 90°
⇒ AO ⊥ BD
⇒ AC ⊥ BD
Hence proved, AC = BD and AC ⊥BD
