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2 years ago

9

The game of checkers is played on a square board. If the length of one side of the board is 4^2 inches, what is the area of the

board in square inches? Express your answer using exponents.

1 answer:

Burka [1]2 years ago

3 0

Answer:

4^4

Step-by-step explanation:

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What numbers are divisble by 23 but are between 2 and 10?

zloy xaker [14]

That is impossible.

For a number to be divisible by 23, it has to be greater than 23.

A number cannot be greater than 23, if you have restricted it to be within the numbers 2 and 10.

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3 years ago

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lesya692 [45]

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Step-by-step explanation:

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3 years ago

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Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?

OlgaM077 [116]

$f(x)=x^2+6x+3$

Complete the square:

$x^2+6x+a^2\implies a=\dfrac{6x}{2x}=3\implies x^2+6x+3^3$

And we have:

$f(x)=x^2+6x+3\\\\f(x)=x^2+6x+3^2-3^2+3\\\\f(x)=(x+3)^2-9+3\\\\\boxed{f(x)=(x+3)^2-6}$

Answer B.

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3 years ago

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

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3 years ago