Answer:
Shrink the primary partition and create a simple volume for Windows 10.
Explanation:
The EFI’s partition space, after it is shrunk, will not be enough to install your Windows 10 since by default; it can only hold a maximum space of about 250MB to 500MB. Some windows versions call this partition EFI while others refer to it as system reserved. Windows uses EFI partition to hold on to essential components that make your PC boot like boot loaders, system utilities, and a few more.
The answer is B.
When you shrink your volume, whether it is local disk C or a primary partition with plenty of free space, it will create unallocated space. Right click on the unallocated space and create a New Simple Volume that will let you format your partition, assign a drive letter, and install your Windows 10 Operating System.
Answer:
Using C language;
#include <stdio.h>
int main()
{
int N, M;
printf("Please enter two numbers: ");
scanf("%d %d", &N, &M);
int P,Q = N*M;
return 0;
}
Explanation:
The variables N and M are declared and the "scanf" function is used to assign a value to the variables from the input prompt, then the product of N and M are saved to the P and Q variables.
<span>This is called an unshielded twisted pair cable, which is also known as a UTP cable. This type of cable has four pairs of wires that are twisted around each other. Because the wires are like this, the electrical interference is reduced.</span>
Answer:
Here is the program for the given question
Explanation:
class StringSet
{
ArrayList<String> arraylist; //a reference variable of ArrayList of generic type String
//A no argument constructor.
public StringSet()
{
arraylist=new ArrayList<String>(); //instantiating the ArrayList object
}
//A mutator that adds a String newStr to the StringSet object.
void add(String newStr)
{
arraylist.add(newStr); // add(String) method to add string to the arraylist
}
//An accessor that returns the number of String objects that have been added to this StringSet object.
int size()
{
return arraylist.size(); // size() method which gives the number of elements in the list
}
//An accessor that returns the total number of characters in all of the Strings that have been added to this StringSet object.
int numChars()
{
int sum = 0;
for(String str:arraylist) //for-each loop; can be read as for each string in arraylist
{
sum+=str.length();
}
return sum;
}
//An accessor that returns the number of Strings in the StringSet object that have exactly len characters.
int countStrings(int len)
{
int count = 0;
for(String str:arraylist)
{
if(str.length() == len)
count++;
}
return count;
}
}
