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3 years ago

HELP PLEASE thank you

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

Answer:

3 books

Step-by-step explanation:

She can carry 3 books in her backpack, this is because 1lb+3lb= 4

and if one book = 2lb each. Then 10-4 =6

so she has 6lb space remaning.

so 6lb divided by 2 = 3

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Lucy has a bag of marbles. She shares one third of them with Carol, keeping one quarter for herself. Amrita joins them, so Lucy

Umnica [9.8K]

Answer:

Step-by-step explanation:

Let L = Lucy, C = Carol and A = Arita , x = Total amount of marbles

Lucy shares 1/3 with Carol and keeps 1/4 for herself.

This means that Carol has 1/3 of the total amount of marbles, Lucy has 1/4 of the total amount of marbles.

C = 1/3x

L = 1/4x

We are also told that Carol has 7 more marbles than Lucy

C = L + 7

Since C = 1/3x and L = 1/4x you can sub these into the above equation and you get:

1/3x = 1/4x + 7

Subtract 1/4x from both sides

1/3x - 1/4x = 7

1/12x = 7

Multiply both sides by 12 to find x.

x = 7 times 12 = 84 (Total amount of marbles = 84)

Amrita gets the remaining number of marbles.

A = x - C - L

A = 84 - 1/3 (84) - 1/4 (84)

A = 35

8 0

3 years ago

If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

3 0

3 years ago

Please choose answer choice a,b,c or d

dmitriy555 [2]

Answer:

A. -4

Step-by-step explanation:

Slope is rise over run, or y2-y1 / x2-x1.

$\frac{y2-y1}{x2-x1} = \frac{-4-8}{2--1} =\frac{-12}{3} = -4$

<u>The slope is A. -4.</u>

Let's see--does that make sense? A slope of four would be pretty steep, and that matches the graph. It also should be negative because the line goes down and to the right, not up and to the right, so -4 makes sense!

4 0

3 years ago

A recent survey of 128 high school students indicated the following information about release times from school.

Delicious77 [7]

Answer:

A) Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

B) The group that wants to get out of school earlier can win after all the votes are counted if their true population proportion takes on a value that is higher than the closest true population proportion (for the group that wants to get out of school later)

That is, in the (31%, 39%) and (35%, 43%) obtained in (a), a range of (35.1%, 39%) and (35%, 38.9%) show how possible that the group that wants to get out of school earlier can win after all the votes are counted.

Step-by-step explanation:

The Interval estimate for the proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Interval estimate = (Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the proportion.

a) Find the interval estimates

i) for those that want to get out earlier and

ii) those that want to get out later.

i) Sample proportion of those that want to get out earlier = 35%

Margin of Error = 4%

Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

ii) Sample proportion of those that want to get out later = 39%

Margin of Error = 4%

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

b) Explain how it would be possible for the group that wants to get out of school earlier to win after all the votes are counted.

Since the interval estimates represent the range of values that the true population proportion can take on for each group that prefer a particular option, the group that wants to get out of school earlier van have their proportion take on values between 31% and 39%. If their true population takes on a value that is highest (which is very possible from the interval estimate), and the group with the highest proportion in the sample, (the group that wants to get out of school later, whose true population proportion can take between 35% and 43%) has a true population proportion that is less than that of the group that wants to get out of school earlier, then, the group that wants to get out of school earlier can win after all the votes are counted.

Hope this Helps!!!

3 0

3 years ago

cassidy loves black and yellow jelly beans she noticed when she was counting them that she had 7 less than three times as many b

Dmitriy789 [7]

Most of the information's are already given in the question. It is important to understand the language of the problem for solving the problem. Once the language is understood, then solving the problem is easy.
Let us assume the number of black jelly beans = x
Number of yellow jelly beans = y
Then from the question we can get to a equation.
3x - 7 = y
We also know from the question that
x + y = 225
x + 3x -7 = 225
4x = 225 + 7
4x = 232
x = 232/4
= 58
So Cassidy has 58 black jelly beans out of the total of 225 jelly beans

4 0

2 years ago