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Rama09 [41]
3 years ago
7

Find the exact value of x

Mathematics
2 answers:
Galina-37 [17]3 years ago
5 0

Answer:

8.94 (Rounded would be 9)

Step-by-step explanation:

By using the Pythagorean Theorem formula,

A^2+B^2 = C^2

You have the hypotenuse (c)  = 12

and you have a leg (a) = 8

and you're trying to find another leg (b) = x

In order to find this, you'll have to change up the formula in order to find (B) instead of (C)

B^2 = C^2 - A^2

(B) = (12)^2 - (8)^2

(B) = 144 - 64

(B) = 80

Square root of 80

B = 8.9

nikitadnepr [17]3 years ago
4 0
Answer: 8.94 (pretty sure)
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A family has two cats named Gordo and Flaco. Gordo weighs 15 pounds and Flaco weighs 8 pounds. A cat’s weight is classified as u
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From the normal distribution table,

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The weight that corresponds to these scores are then calculated.

Standardized scores are given as

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z' = (limit for the bottom 5% - μ)/σ

-1.645 = (limit for the bottom 5% - 9.5)/1.5

limit of the bottom 5% = (-1.645)(1.5) + 9.5 = 7.033 pounds

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1.645 = (limit for the top 5% - 9.5)/1.5

limit of the bottom 5% = (1.645)(1.5) + 9.5 = 11.968 pounds

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Gordo's weight = 15 pounds

It is outside the healthy weight range and is in the top 5% of weights of cats.

Gordo's weight makes the cat unhealthy.

Flaco's weight = 8 pounds

Flaco's weight lies in the healthy weight range for cats. Hence, Flaco is a healthy cat.

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If x^3 + 1/x^3 = 110 then find x + 1/x
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Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)

therefore

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