1/2, 4/8. If in decimal form, you can also do 0.5 or 0.500
Answer:
I want to say 6.75 just because it's to small tho
Step-by-step explanation:
3x-12 = 12x
-12 = 9x
-12/9 = x
x= -4/3
Answer:
![P(Y| X = 65)=66](https://tex.z-dn.net/?f=P%28Y%7C%20X%20%3D%2065%29%3D66)
Step-by-step explanation:
From the question we are told that:
Mean![\=x=70](https://tex.z-dn.net/?f=%5C%3Dx%3D70)
Standard Deviation ![\sigma=3](https://tex.z-dn.net/?f=%5Csigma%3D3)
Variance ![\sigma^2=2](https://tex.z-dn.net/?f=%5Csigma%5E2%3D2)
Generally the equation for Variance of Prediction is mathematically given by
![\sigma_{p}^2=\sigma_{p}'^2*(1-r^2)](https://tex.z-dn.net/?f=%5Csigma_%7Bp%7D%5E2%3D%5Csigma_%7Bp%7D%27%5E2%2A%281-r%5E2%29)
Where
![\sigma_{p}'^2=variance\ of\ predictor](https://tex.z-dn.net/?f=%5Csigma_%7Bp%7D%27%5E2%3Dvariance%5C%20of%5C%20predictor)
Therefore
![2=3^2*(1-r^2)\\\\r=0.88](https://tex.z-dn.net/?f=2%3D3%5E2%2A%281-r%5E2%29%5C%5C%5C%5Cr%3D0.88)
Therefore
The Average score of student in 2nd test
![P(Y| X = x) = \mu +\frac{p\sigma}{\sigma(x −\mu_X)}](https://tex.z-dn.net/?f=P%28Y%7C%20X%20%3D%20x%29%20%3D%20%5Cmu%20%2B%5Cfrac%7Bp%5Csigma%7D%7B%5Csigma%28x%20%E2%88%92%5Cmu_X%29%7D)
![P(Y| X = 65) = 70 +0.88\frac{3}{3)}*(65-70)](https://tex.z-dn.net/?f=P%28Y%7C%20X%20%3D%2065%29%20%3D%2070%20%2B0.88%5Cfrac%7B3%7D%7B3%29%7D%2A%2865-70%29)
![P(Y| X = 65)=66](https://tex.z-dn.net/?f=P%28Y%7C%20X%20%3D%2065%29%3D66)