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2 years ago

10. Given that the areas of the two rectangles are equal, calculate the

Mathematics

1 answer:

Virty [35]2 years ago

4 0

Answer:1251231

Step-by-step explanation:

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Use the table to find the relationship between the two quantities.

olchik [2.2K]

Answer:

the answer is 3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Is the point 3/5 and 4/5 corresponds to an angle in the unit circle what is the csc

Mariulka [41]

Answer:

csc = 5/4

Step-by-step explanation:

Assuming that the two given points 3/5 and 4/5 are the two sides of a triangle and a right angle 0 with legs x and y and z as its hypotenuse.

Then using Pythagoras Theorem:

$z^2=x^2+y^2$

$z^2=(\frac{3}{5} )^2+(\frac{4}{5} )^2$

$z^2 = \frac{9}{25} + \frac{16}{25}$

$z^2=\frac{25}{25}$

$z^2=1$

Taking square root on both the sides:

$z=1$

Now, $sin\alpha=\frac{4}{5}$

and we know that $csc = \frac{1}{sin\alpha }$

Therefore, csc = 5/4.

8 0

3 years ago

Please help me I need help please

MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

Standard equation of a circle:

$(x-a)^2+(y-b)^2=r^2$

(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

$\implies p=1+3=4$

Additional information

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

$\implies x^2-4x+y^2+6y=16$

$\implies (x-2)^2-4+(y+3)^2-9=16$

$\implies (x-2)^2+(y+3)^2=16+4+9$

$\implies (x-2)^2+(y+3)^2=29$

So this is a circle with centre (2, -3) and radius √29

3 0

2 years ago

Select the correct answer.

torisob [31]

Answer:

C. - f(x) = f( - x)

Step-by-step explanation:

Property of the odd function is:

- f(x) = f( - x)

Same applies to the given function:

f(x) = -2x⁵ + x³ - 7x
f(- x) = -2(-x)⁵ + (- x)³ - 7(-x) = 2x⁵ - x³ + 7x = - (2x⁵ + x³ - 7x) = - f(x)

4 0

2 years ago

Keith played the first 22 minutes of soccer game lohan then replaced him for the rest of half logan started the second half and

insens350 [35]

Answer:

Logan played for 22 minutes during the second half.

Step-by-step explanation:

Since Keith played the first 22 minutes of a soccer game and Logan then replaced him for the rest of the half, and Logan started the second half and was replaced by Wilson with 18 minutes left in the game, if each half is 40 minutes long To determine how long did Logan play during the second half, the following calculation must be performed:

Second Half Total - Time Played by Wilson = Time Played by Logan

40 - 18 = X

22 = X

Therefore, Logan played for 22 minutes during the second half.

6 0

2 years ago