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trapecia [35]
3 years ago
10

What is the graph for the transforming function y=−(−x) 2

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

axis of symmetry is x=0

vertex is (0,0)

Step-by-step

math

way is good to use it's a calculator site

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Select the rational expression that is equivalent to the given expression below. 4 over x - 3
Ad libitum [116K]
When you say 1 over 3, you are basically saying 1 divided by 3, or expressed as a rational number: \frac{1}{3}. in our rational number the denominator is 1, and the numerator is 3

Now, a rational expression is an algebraic expression in a rational for. If we apply the same to your problem. 4 over x-3 means 4 divided by x-3, or in mathematical notation: \frac{4}{x-3}. In this case, the numerator is 4, and the denominator is x-3.

We can conclude that the equivalent rational expression of <span>4 over x - 3 is </span>\frac{4}{x-3}.

4 0
3 years ago
Which statement is true about the value of the expression below?<br> PLEASE HELP
Naily [24]

Answer:

The answer is It is between 0 and 1

Step-by-step explanation:

If you solve the problem step by step as (-2^3)^-2<1 then it comes out as true so it would be less than 1 but more then 0.

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Amanda [17]

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Imagine it as a mirror or like a paper folding in half, then figure out the direction it shifts.

4 0
3 years ago
A figure is shown below.
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Find the exact trigonometric ratios for the angle x whose radian measure is given. (if an answer is undefined, enter undefined.)
Inga [223]
Given the angle \frac{3\pi}{4}

angle \frac{3\pi}{4} is equivalent to angle 135 degrees and angle 135 degrees is equvalent to angle 45 degrees in the second quadrant, thus sine is positive but cosine and tangent are negative.

\sin \frac{3\pi}{4} =\sin \frac{\pi}{4} = \frac{1}{ \sqrt{2} }  \\  \\ \csc\frac{3\pi}{4}= \frac{1}{\sin\frac{3\pi}{4}} = \frac{1}{\frac{1}{ \sqrt{2} }} = \sqrt{2}  \\  \\ \cos\frac{3\pi}{4} =-\cos \frac{\pi}{4} = -\frac{1}{ \sqrt{2} }  \\  \\ \sec\frac{3\pi}{4}= \frac{1}{\cos\frac{3\pi}{4}} = \frac{1}{-\frac{1}{ \sqrt{2} }} =- \sqrt{2}  \\  \\ \tan\frac{3\pi}{4} =-\tan \frac{\pi}{4} = -1  \\  \\ \cot\frac{3\pi}{4}= \frac{1}{\tan\frac{3\pi}{4}} = \frac{1}{-1} =- 1
8 0
3 years ago
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