Answer:
Step-by-step explanation: I don't
Answer:
Solution given:
m∠ADB=(4x−12)°
m∠CDB=(3x+6)°
m∠ADC =?
Since diagonal BD bisect the angle <ADC
so
m∠ADB= m∠ADC
(4x-12)°=(3x+6)°
4x-3x=6-12
x=12+6
x=18°
again.
<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°
So
<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>
The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
So the hypotenuse is 2.7, and the opposite is 1.6.
We can use sine to find the angle.
sin(x) = (1.6)/(2.7)
Simplify:
sin(x) = 0.592592593
Plug this in your calculator to find the inverse of sine:
x = 36.34120312
So the angle is 36 degrees.
-3.7 is greater than -3.8, but is it not less than of equal to -3.8
