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GarryVolchara [31]
3 years ago
14

1.whats the difference -2 -6

Mathematics
1 answer:
zzz [600]3 years ago
4 0
1.A)-8........2.C)1/12
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Explain: every equilateral triangle is isosceles, but not every isosceles triangle is equilateral
8_murik_8 [283]
Okay, in isosceles triangle two sides are equal and in equilateral triangle all sides are equal.
so in a equilateral triangle amy two sides can be equal, but in isosceles triangle all the three sides can't be equal.
8 0
4 years ago
Read 2 more answers
(a) Consider a class with 30 students. Compute the probability that at least two of them have their birthdays on the same day. (
Galina-37 [17]

Answer:

a.) 0.7063

b.) 23

Step-by-step explanation:

a.)

Let X be an event in which at least 2 students have same birthday

     Y be an event in which no student have same birthday.

Now,

P(X) + P(Y) = 1

⇒P(X) = 1 - P(Y)

as we know that,

Probability of no one has birthday on same day = P(Y)

⇒P(Y) = \frac{365!}{(365)^{n} (365-n)! }      where there are n people in a group

As given,

n = 30

⇒P(Y) = \frac{365!}{(365)^{30} (365-30)! } = \frac{365!}{(365)^{30} (335)! } = 0.2937

∴ we get

P(X) = 1 - 0.2937 = 0.7063

So,

The probability that at least two of them have their birthdays on the same day  =  0.7063

b.)

Given, P(X) > 0.5

As

P(X) + P(Y) = 1

⇒P(Y) ≤ 0.5

As

P(Y) = \frac{365!}{(365)^{n} (365-n)! }

We use hit and trial method

If n = 1 , then

P(Y) = \frac{365!}{(365)^{1} (365-1)! } = \frac{365!}{(365)^{1} (364)! }  = 1 \nleq 0.5

If n = 5 , then

P(Y) = \frac{365!}{(365)^{5} (365-5)! } = \frac{365!}{(365)^{5} (360)! }  = 0.97 \nleq 0.5

If n = 10 , then

P(Y) = \frac{365!}{(365)^{10} (365-10)! } = \frac{365!}{(365)^{10} (354)! }  = 0.88 \nleq 0.5

If n = 15 , then

P(Y) = \frac{365!}{(365)^{15} (365-15)! } = \frac{365!}{(365)^{15} (350)! }  = 0.75 \nleq 0.5

If n = 20 , then

P(Y) = \frac{365!}{(365)^{20} (365-20)! } = \frac{365!}{(365)^{20} (345)! }  = 0.588 \nleq 0.5

If n = 22 , then

P(Y) = \frac{365!}{(365)^{22} (365-22)! } = \frac{365!}{(365)^{22} (343)! }  = 0.52 \nleq 0.5

If n = 23 , then

P(Y) = \frac{365!}{(365)^{23} (365-23)! } = \frac{365!}{(365)^{23} (342)! }  = 0.49 \nleq 0.5

∴ we get

Number of students should be in class in order to have this probability above 0.5 = 23

5 0
3 years ago
4y=-2(5-2y) what is y​
Montano1993 [528]

Answer:

no solution

Step-by-step explanation:

4y=-2(5-2y)

=4y = -10+4y

= 4y-4y=-10+4y-4y

=0-10

= undefined

5 0
3 years ago
PLEASE HELP ASAP OF YOU DO FOD BLESS YOU BECAUSE IT WILL RAISE MY GRADE
Sati [7]

Answer:

8

Step-by-step explanation:

The basic form of the equation is y=mx+b. The b stands for the y-intercept. In this equation, 8 is b due to its position in the equation, and -8/7 is m. Since we know that 8 is b and that b is the y-intercept, we know that 8 is the y-intercept.

Hope this helps!

4 0
2 years ago
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Write an equation for the linear function whose graph contains the points (-1 ,-2) and (3, 10)?
Fofino [41]

Answer:

y+2 =3(x+1)

Step-by-step explanation:

Firstly I will find slope of this linear function:

m=(y-yo) / (x-xo)

m=(-2-10)/(-1-3)

m=-12/-4

m=3

Replacing A(-1-2) :

(y-yo)=m(x-xo)

3 0
3 years ago
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