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OLga [1]
4 years ago
14

What is the additive inverse of the complex number 9 – 4i?

Mathematics
1 answer:
stiks02 [169]4 years ago
8 0

Answer:-(9 - 4i) =

Step-by-step explanation:

Given the complex number 9 - 4i, the additive inverse is the number that when added to the original number, would equate to zero. Another term this may be known as is the additive identity. The additive inverse is simply:

(a + bi) = -(a + bi)

Given: 9 - 4i

-(9 - 4i) = -9 + 4i

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In this exercise, we consider strings made from uppercase letters in the English alphabet and decimal digits.
Yuri [45]

Answer:

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  • b) 21\cdot10\cdot36^7
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Step-by-step explanation:

We will use the product rule from combinatorics.

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  • b) We have 5 possible choices for the first character, it must be some vowel a,e,i,o,u. The second character can be chosen in 21 ways, selecting some consonant. There are 10 possibilities for the last character because only of the digits are allowed. The other seven characters have no restrictions, so each one can be chosen in 36 ways. By the product rule there are 21\cdot 10\cdot 36^7 strings.    
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