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3 years ago

What is the additive inverse of the complex number 9 – 4i?

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

Answer:-(9 - 4i) =

Step-by-step explanation:

Given the complex number 9 - 4i, the additive inverse is the number that when added to the original number, would equate to zero. Another term this may be known as is the additive identity. The additive inverse is simply:

(a + bi) = -(a + bi)

Given: 9 - 4i

-(9 - 4i) = -9 + 4i

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Answer:

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Step-by-step explanation:

The symbol U is the union symbol, which denotes the union of two sets.

This means that given two sets A and B, the expression

A U B

indicates all the elements that belong to either set A or set B.

In this problem, we have the following two sets:

A = {19, 20, 21, 24}

B = {17, 19, 20, 22}

We can therefore list all the elements belonging to either set A or set B, they are:

17, 19, 20, 21, 22, 24

So, the expression A U B indicates the set:

A U B = {17, 19, 20, 21, 22, 24}

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