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OLga [1]
3 years ago
14

What is the additive inverse of the complex number 9 – 4i?

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:-(9 - 4i) =

Step-by-step explanation:

Given the complex number 9 - 4i, the additive inverse is the number that when added to the original number, would equate to zero. Another term this may be known as is the additive identity. The additive inverse is simply:

(a + bi) = -(a + bi)

Given: 9 - 4i

-(9 - 4i) = -9 + 4i

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9514 1404 393

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__

<em>Additional comment</em>

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