$\text{The domain}\\2x-6\neq0\ \wedge\ 6x-18\neq0\to x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2(x-3)}=\dfrac{9}{6(x-3)}\ \ \ |\cdot6\\\\\dfrac{3x^2}{x-3}=\dfrac{9}{x-3}\iff3x^2=9\ \ \ |:3\\\\x^2=3\to x=\pm\sqrt3$

4 0

2 years ago

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I need help for this question

Nikitich [7]

V=V of cube- V pyramid= 8^3- 7^2*8/3=512-49*8/3=512-130,67=381.33 cm^3

7 0

3 years ago

Select the property of equality used to arrive at the conclusion <br> if x-3=7 , then x=10

Fantom [35]

Answer:

The addition property of equality

Step-by-step explanation:

According to the addition property of equality, if we add the same number to each side of an equation, the equality is still true.

We are given the equation

x – 3 = 7, and we must solve for x.

We want to get x by itself, so we <em>add 3 to each side</em>.

x – 3 + 3 = 7 + 3

x = 10

We have just used the addition property of equality.

8 0

3 years ago

I want to build a deck around my pool that is the same width all the way around. If the pool is 8meters by 10meters and I have e

anastassius [24]

Answer:

Step-by-step explanation:

4 0

2 years ago