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3 years ago

The acceleration due to gravity is the constant of variation. What is the acceleration due to gravity of a falling object?

Mathematics

2 answers:

nikklg [1K]3 years ago

4 0

9.8 because that is the rate

MatroZZZ [7]3 years ago

3 0

Answer:

Option B

Step-by-step explanation:

For a freely falling body or object the acceleration would be the acceleration due to gravity

This would vary depending on the system we choose.

If we choose m/sec ^2 i.e. metric system

acceleration due to gravity = $9.8m/sec^2$

In FPS system

acceleration due to gravity $= 32.17 ft/sec^2$

Out of 4 options we find that option B is right.

You might be interested in

A mustard seed weighs approximately 0.000004409 pounds. Estimate the weight of a mustard seed in pounds by writing it in the for

Tanya [424]

I'm not for sure but I think it might be 4409 to the -6 so 4409^-6. I haven't done these in a while so I might be wrong!

5 0

3 years ago

Pat picked a card from a standard deck, looked at it, and then put it back. He then picked a second card. What is the probabilit

AlekseyPX

Answer: 17/52

Step-by-step explanation:

There are 52 total cards in a standard deck.

The number of diamonds in a deck of cards is 13 and there are 4 jacks in a deck of cards.

So the propabibilty of Pat picking a diamond is 13/52 and the probability of Pat picking a jack is 4/52. Now you have to add the two probabilities together.

You do not remove any digits because Pat put the card back into the deck, he didn't take it away. So we do not take away from the total

13 + 4 = 17

You do not need to change the denominator cause 52 is the same.

So 17/52 is the probability of Pat picking a diamond or a jack

I hope this helped!

3 0

3 years ago

What is the equation for the vertical asymptote of the function shown below? f(x)=3x^4-3/2x-5

levacccp [35]

$f(x)= \frac{3x^4}{2x-5}$

the va's are where x is undefined, or where the denomenator is zero
first simplify if applicable
cannot simplify

set denom to zero
2x-5=0
2x=5
x=2.5

the vertical assemtote is vertical so it is x=2.5 or 5/2

the VA is x=5/2

3 0

2 years ago

A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro

Mrac [35]

Answer:

The equation of the displacement $d$ as a function of time $t$ is :

$d(t)=8sin(\pi t+\pi )$

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple $sin$ or $cos$ terms.

Thus,

$d(t) = Asin(wt+c)$

is the general form of displacement of a SHM.

where,

$d(t)$ is the displacement with respect to the mean position at any time $t$
$A$ is amplitude
$w$ is the natural frequency of oscillation ( $rads^{-1}$ )
$c$ is the phase angle which indicates the initial position of the object in SHM ( $rad$ )