The acceleration due to gravity is the constant of variation. What is the acceleration due to gravity of a falling object?
2 answers:
Answer:
Option B
Step-by-step explanation:
For a freely falling body or object the acceleration would be the acceleration due to gravity
This would vary depending on the system we choose.
If we choose m/sec ^2 i.e. metric system
acceleration due to gravity =
In FPS system
acceleration due to gravity
Out of 4 options we find that option B is right.
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We are given coordinates of the triangle: A(2,2), B(7,1) and C(8,-4).
We need to rotated 90° counterclockwise about the origin.
In order to find the new coordinates of rotatation 90°counterclockwise about the origin, we can apply rule (h, k) ---> (-k,h).
Where (h,k) are the coordinates of original image on axes and (-k,h) are the coordinates of rotated image.
In resulting coordinates of the image first swap the x and y coordinates of the original image and then make the sign opposite of each x-coordinate.
On applying rule (h, k) ---> (-k,h), we get
A(2,2) --> A'(-2,2)
B(7,1) --> B'(-1,7)
C(8,-4) --> C'(4,8)
