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3 years ago

6

What is the lateral area of the cylinder?

1 answer:

hoa [83]3 years ago

6 0

The lateral area of the cylinder is AL=2 pi r h
the r is for radius and h is for height.

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PLEASE HELP!!!!!!!!!!!!!

Marianna [84]

Answer:

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Step-by-step explanation:

formula for area of a triangle is base * width * 1/2

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3 years ago

Write an equation of the line passing theough the point (4,-1) and perpendicular to the line y=2x-5.

Gwar [14]

Icons ojzo kook oak am

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3 years ago

On the exam, Rebecca successfully created 20 out of 25 vases.

juin [17]

$\text{Hello there! :]}$

$\large\boxed{125 \text { vases}}$

$\text{To solve, find the proportion of successes from the total:}\\\\20 / 25 = 4 / 5\\\\\text{Set up a proportion to find the # of vases necessary to complete 100 successfully:}\\\\\frac{20}{25} = \frac{100}{x} \\\\\text{Cross multiply to solve:}\\\\20 * x = 100 * 25\\\\20x = 2500\\\\\text{Divide both sides by 20:}\\\\x = 125 \text{ vases}$

7 0

3 years ago

Read 2 more answers

Solve the system using elimination.<br> 2x + 18y = -9<br> 4x + 18y = -27

Elan Coil [88]

First, let's cancel out the x by multiplying 2x + 18y = -9 by -2.

-2 ( 2x + 18y = -9) = -4x -36y = 18

Then, we combine the two equations.

-4x + 4x = 0

18y - 36y = -18y

-27 + 18 = -9

Our new equation is -18y = -9.

Now, divide both sides by -18.

-18y / -18 = y

-9/ -18 = 1/2

y = 1/2

We can plug in a value for y since y = 1/2 now.

Let's use 2x + 18y = -9

Plug in y.

2x + 18(1/2) = -9

2x + 9 = -9

Then, subtract 9 from both sides.

2x = -18

Divide by 2.

2x/2 = x

-18/2 = -9

x = -9

Lastly, we can plug in both x and y values to see it works.

2(-9) + 18(1/2) = -9

-18 + 9 = -9

Therefore, the values of x and y does work.

x = -9

y = 1/2

4 0

3 years ago

Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin

levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

$3\frac{3}{5}=\frac{18}{5}$ sq meters

Grandmother's wrapping paper:

$1\frac{1}{2}=\frac{3}{2}$ sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

$=\frac{18}{5}+\frac{3}{2}$

$=\frac{36}{10}+\frac{15}{10}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}$

$=\frac{36+15}{10}$

$=\frac{51}{10}$

Therefore, total wrapping papers Serena and her grandmother = 51/10

3 0

3 years ago