$x=\sqrt{880-8x}\\
D:880-8x\geq0 \wedge x\geq0\\
D:8x\leq880 \wedge x\geq0\\
D:x\leq 110 \wedge x\geq0\\
D:x\in\langle0,110\rangle\\
x^2=880-8x\\
x^2+8x-880=0\\
x^2+8x+16-896=0\\
(x+4)^2=896\\
x+4=8\sqrt{14} \vee x+4=-8\sqrt{14}\\
x=-4+8\sqrt{14} \vee x=-4-8\sqrt{14}\\
\\ x=-4-8\sqrt{14}\not \in D \Rightarrow \boxed{x=-4+8\sqrt{14}}$

5 0

3 years ago

HELP PLEASE. 3(2x+3)=15

pantera1 [17]

If you are solving for X then we have to do a few process

What you would want most is to remove the parentheses, so to do that i would use distributive property

3*2x is 6x and 3*3 is 9 so our new equation will look like

6x+9=15 if you don't understand please tell me

now we must bring the 9 over

If you bring the 9 over than it would become negative

6x=15-9

so 6x=6

and now you can solve the answer is x=1

7 0

2 years ago

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