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nikdorinn [45]
3 years ago
10

Lydia is making spaghetti sauce at a community luncheon. Each batch requires 1⁄2 teaspoon of salt, 1⁄3 teaspoon of oregano, 1⁄4

teaspoon of crushed thyme, and 1⁄8 teaspoon of black pepper. Which spice is used in the largest quantity in Lydia's recipe?
Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Salt is used in the largest quantity in Lydia's recipe.

<em><u>Explanation</u></em>

Required spices are......

Salt = \frac{1}{2} teaspoon , Oregano = \frac{1}{3} teaspoon, Crushed thyme = \frac{1}{4} teaspoon and Black peeper = \frac{1}{8} teaspoon

For finding the largest quantity, first we need to make the denominators of each fraction as equal and then identify the largest numerator.  

The denominators are 2, 3, 4 and 8 and their LCM(Least common multiple) will be 24. So.....

\frac{1}{2}= \frac{1*12}{2*12}=\frac{12}{24} \\ \\ \frac{1}{3}=\frac{1*8}{3*8}=\frac{8}{24}\\ \\ \frac{1}{4}=\frac{1*6}{4*6}=\frac{6}{24}\\ \\ \frac{1}{8}=\frac{1*3}{8*3}=\frac{3}{24}

As the largest numerator is 12 here, so the value of \frac{1}{2} is largest among all the fractions.

Thus, <u>Salt</u> is used in the largest quantity in Lydia's recipe.

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Please help :)))) ( attachment )
Anastaziya [24]
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2

This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that 

g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2

So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).


Here's proof of both claims

-----------------------------------------

Proof of Claim 1:

f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6

-----------------------------------------

Proof of Claim 2:

h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
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