the discriminant formula is b^2-4ac
so plug the values from each equation into the formula and solve, the result is the value of the discriminant
if the number is negative, there are no real roots/x-int
if it is 0 there is one real root/x-intercepts
if it is positive it has 2 real roots/x-int
and to find the actual solutions you have to plug the values into the quadratic formula
Answer:
x = -5
y = 6
Step-by-step explanation:
3x + 7y = 27 --------------(I)
-3x + y = 21 -----------(II)
Add equation (I) & (II) and so x will be eliminated and we can find the value of y.
(I) 3x + 7y = 27
(II) <u> -3x + y = 21 </u> {add}
8y = 48
y = 48/8
y = 6
Plugin y = 6 in equation (I)
3x +7*6 = 27
3x + 42 = 27
3x = 27 - 42
3x = -15
x = -15/3
x = -5
Step-by-step explanation:
x²/(x²-9) + 1/(x-3) = 1/(4x-12)
4x² + 4(x+3) = 1
4x² + 4x + 11 = 0
Since the discriminant is negative, there are no real solutions.
You need to solve 5 equations
1. 7x - 2.1 = 14.1
2. 7x - 2.1 = 30.9 and so on
1. 7x - 2.1 = 14.1
7x = 16.2
x = 2.314 so first number in the domain is 2.314
You can calculate the other 4 in the same way
<span>you can solve all quadratic equations using this method:
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x^2 + 4x + 4 = 0
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the above quadratic equation is in standard form, with a=1, b=4, and c=4
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 4 4
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has ONE real root (the x-intercept), which is:
x = -2
x = -2
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x^2 + x = 0
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the above quadratic equation is in standard form, with a=1, b=1, and c=0</span>