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Kisachek [45]
3 years ago
12

According to a study conducted by the Toronto-based social media analytics firm Sysomos, of all tweets get no reaction. That is,

these are tweets that are not replied to or retweeted (Sysomos website, January ). Suppose we randomly select tweets.a. What is the expected number of these tweets with no reaction (to the nearest whole number)
a) What is the expected number of these tweets with no reaction?
b) What are the variance and standard deviation for the number of these tweets with no reaction?
Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

a) E(X) = 71

b) V(X) = 20.59

Sigma = 4.538

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>According to a 2010 study conducted by the Toronto-based social media analytics firm Sysomos, 71% of all tweets get no reaction. That is, these are tweets that are not replied to or retweeted (Sysomos website, January 5, 2015). </em>

<em> Suppose we randomly select 100 tweets. </em>

<em>a) What is the expected number of these tweets with no reaction? </em>

<em>b) What are the variance and standard deviation for the number of these tweets with no reaction?</em>

This can be modeled with the binomial distribution, with sample size n=100 and p=0.71, as the probability of no reaction for each individual tweet.

The expected number of these tweets with no reaction can be calcualted as the mean of the binomial random variable with these parameters:

E(X)=n\cdot p=100\cdot 0.71=71

The variance for the number of these tweets with no reaction can be calculated as the variance of the binomial distribution:

V(X)=np(1-p)=100\cdot0.71\cdot0.29=20.59

Then, the standard deviation becomes:

\sigma=\sqrt{V(X}=\sqrt{20.59}=4.538

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What is 73.24 rounded to the nearest tenth
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Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.

A random sample of <em>n</em> = 111 keypads is analyzed.

Then the sampling distribution of \hat p is:

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Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

P(0.72

                             =P(-1.25

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

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