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sergejj [24]
3 years ago
15

Chef Daniel had 431 ounces of chocolate frosting in his refrigerator. It takes 8 ounces of frosting to frost one cupcake. How ma

ny cupcakes can he frost
Mathematics
2 answers:
Alex3 years ago
7 0

Answer:

53 cupcakes

Step-by-step explanation:

Take the amount of frosting and divide by the amount needed per cupcake

431/8

53.875

We round down since we cannot frost part of a cupcake

53 cupcakes

mrs_skeptik [129]3 years ago
4 0

Answer:

53 cupcakes

Step-by-step explanation:

He has a total of 431 ounces and each cupcake needs 8 ounces of frosting. Therefore can divide the total amount of frosting (431 ounces) by the amount per cupcake (8 ounces)

total amount/ amount per cupcake

431 ounces/8 ounces

431/8

53.875

0.875, or a fraction/part of a cupcake can’t be frosted, so we should round down to the nearest whole number.

53

He can frost 53 cupcakes.

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Mumz [18]
Simple boy learn idk lol im a student
5 0
3 years ago
Read 2 more answers
There are many square prisms with volume 125 in. Let w represent the side length of the square base and h represent the height i
iogann1982 [59]

Answer:

5in by 5in by 5in

Step-by-step explanation:

We are not told wat to find but we can as well find the dimension of the prism that will minimize its surface area.

Given

Volume = 125in³

Formula

V = w²h ..... 1

S = 2w²+4wh ..... 2

w is the side length of the square base

h is the height of the prism

125 = w²h

h = 125/w² ..... 3

Substitute eqn 3 into 2 as shown

S = 2w²+4wh

S = 2w²+4w(125/w²)

S = 2w²+500/w

To minimize the surface area, dS/dw = 0

dS/dw =4w-500/w²

0= 4w-500/w²

Multiply through by w²

0 = 4w³-500

-4w³ = -500

w³ = 500/4

w³ =125

w = cuberoot(125)

w = 5in

Get the height

125 =w²h

125 = 25h

h = 125/25

h = 5in

Hence the dimension of the prism is 5in by 5in by 5in

5 0
3 years ago
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
N76 [4]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

3 0
3 years ago
2. Graph the following equation: y = - 1/2 x + 4
Murljashka [212]

Answer:

Step-by-step explanation:

y = (-1/2)x + 4 is the equation of a straight line with y-intercept (0, 4) and slope -1/2.

To graph this, first plot the y-intercept (0, 4).

Recall that slope m = rise / run, and notice that the slope in this particular case is -1/2 = rise / run, or rise = -1 and run = 2.

Starting with your pencil point on (0, 4), move the point 2 units to the right (run = 2), arriving at (2, 4).  Next, move your pencil point 1 unit down, to (2, 3).

Draw a straight line through (0, 4) and (2, 3).

8 0
3 years ago
A truck can be rented from Company A for ​$110 a day plus ​$0.80 per mile. Company B charges ​$30 a day plus ​$0.90 per mile to
grin007 [14]

Answer:

800 miles

Step-by-step explanation:

Let the number of miles be represented by x

Company A for ​$110 a day plus ​$0.80 per mile.

$110 + $0.80 × x

110 + 0.80x

Company B charges ​$30 a day plus ​$0.90 per mile to rent the same truck.

$30 + $0.90 × x

30 + 0.90x

110 + 0.80x = 30 + 0.90x

110 - 30 = 0.90x - 0.80x

80 = 0.1x

x = 80/0.1

x = 800 miles

800 miles driven per day makes the rental cost for Company A a better deal than Company​ B's

6 0
3 years ago
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