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Vinil7 [7]
2 years ago
7

Y = -4.5x + 15 is this not a function, linear function, or nonlinear function

Mathematics
1 answer:
crimeas [40]2 years ago
5 0
This is a linear function
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Fully simplify 7c - 4h - 2c - 5h​
astraxan [27]

Answer:

5c-9h

Step-by-step explanation:

1) 7c-4h-2c-5h

2) 5c-4h-5h

3) 5c-9h

4 0
1 year ago
The value of a bank account, y, increases by 5% each year, x. If the initial value of the account is $800, which equation repres
Mashcka [7]

Answer:

Equation to represent the situation = 800=Y(1.05)^X

Step-by-step explanation:

Given:

Initial investment = Y

Growth rate (r) = 5% = 5 / 100 = 0.05

Number of year (n) = X year

Amount after X year = $800

Find:

Equation to represent the situation:

Computation:

Amount = Initial\ investment (1+r)^n\\\\800 = Y (1+0.05)^X\\\\800 = Y (1.05)^X\\\\

Equation to represent the situation = 800=Y(1.05)^X

6 0
3 years ago
Why is the polynomial, 4x^2y + 5xy classified as a 3rd degree binomial?
Ronch [10]
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6 0
3 years ago
. Which volume-to-surface-area ratio would be better for an ice cube— the lowest possible or the highest possible? Use the table
Oxana [17]

The volume-to-surface-area ratio would be better for an ice cube is the highest possible one.

<h3>How to explain the volume?</h3>

When you put ice into your drink, the goal is to have the ice chill your drink. This takes time. Therefore, you would want the ice to slowly melt and cool the drink for as long as you can.

You would want to have the highest possible volume to surface area ratio in an ice cube. If your ice cube is mostly surface area with less volume, it will melt quickly and water down your drink. If your ice cube has a higher ratio of volume to the surface area, it will stay solid longer and chill your drink longer.

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4 0
2 years ago
Writing Equations from Unit Rate
liq [111]
Y=3.25x should be the most probable choice because 6.50 is the price of 2 pounds of candy and once it’s divided by 2 the equation will show how much the unit rate is or the price of each pound of candy.
6 0
3 years ago
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