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lapo4ka [179]
3 years ago
14

A car dealership sells sedans and SUVs. In 2000, the ratio in which they were sold was 5:4. By 2010, the dealership had adjusted

its inventory to a 2:7 ratio. The car dealership sold the same total amount of vehcles in both years. If it sold 84 SUVs in 2010, then how many sedans did it sell in 2000?
Mathematics
2 answers:
seropon [69]3 years ago
7 0

Answer:

The number of sedans sold in 2000 is:

  • <u>60 sedans</u>.

Step-by-step explanation:

In the first instance, remember that the 5: 4 ratio of the year 2000 means that for every 5 cars of one type, four of another were sold (in this case sedans and SUVs), since in 2010 it is mentioned that the ratio changed a 2: 7 is the one that must be taken into account to calculate with the data of 84 SUVs sold.

1. Since you have the number of SUVs sold and the ratio (7) divide the total number of cars sold in the ratio to identify the unit on the scale:}

  • 84 / 7 = 12

Now to identify the number of sedans sold in 2010 you multiply the unit by the scale (2):

  • 12 * 2 = 24

Add the number of sedans and SUVs to identify the total number of cars sold in 2010:

  • 84 + 24 = <u>108 cars</u>.

<u>Since you already know the total number of cars and it is said that in the two years registered it was the same, you already know the number of cars sold in 2000 (108 also)</u>, so you can add the scales for the year 2000 and divide the total of cars on these scales to obtain the unit:

  • 5 + 4 = 9
  • 108 / 9 = 12

Since you have the unit of 12 again, you can multiply this value by the scale you are looking for (in the case of the question that of the sedans sold) and you will get the number of cars sold from that reference (5):

  • 5 * 12 = <u>60 sedans sold in 2000</u>
babymother [125]3 years ago
4 0
120 would be the correct answer on apex
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Mamont248 [21]

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The answer is 131 people

Step-by-step explanation:

I'm not too sure about equations bc its been a min since I've done them but maybeeeee it's 26x - (1,575) = 5,000 something like that LOL

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