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vazorg [7]
3 years ago
8

A dice game lets you roll 2 6 sided disc and find the sum of the numbers. A 12 wins 100 dollars, 10 or 11 wins 50 dollars, a 2 w

ins 3 dollars. The game costs 6 dollars to play. What is th expected outcome of this game?
Mathematics
1 answer:
Advocard [28]3 years ago
4 0

Answer:

Step-by-step explanation:

A two 6 sided die is rolled

Sample space would be (1,1)...(1,6)....(6,1)....(6,6)

Let x be the sum obtained

X can take values as 2 or 3 ....12

P(x=12) = P(6,6) =1/36

P(x=10 or 11) = P{(5,5)(5,6) (6,5) (4,6)(6,4)}=5/36

P(2) =P(1,1) = 1/36

For other outcomes no payment

Thus we can list this as

Sum       2     3         4        5      6    7    8     9    10 or 11     12

Prob       1/36                                                            5/36      1/36

Gain        3      0       0        0      0    0    0     0        50         100

E(gain)   3/36  0        0       0       0   0     0    0        250/36   100/36

E(gain) = total= 353/36

Cost of game = 6

E(outcome) = E(gain -6) = E(gain)-6 = 353/36 -6

= 3.806

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Multiply and reduce to lowest terms <br> 5/13 X 3 3/8
Ganezh [65]

Answer:

<h2>1 31/104</h2>

Step-by-step explanation:

First, let's turn them both into improper fractions.

3 3/8 = 27/8

Now we can multiply

It is 5*27 / 13 * 8

This equals: 135 / 104

Simplified even further is:

1 31/104

6 0
2 years ago
X+4,x+12,x-1 and x+5 are in proportion.find the value of x
Anastaziya [24]

Answer:

Step-by-step explanation:

As they are in proportion,

x +4  : x +12   :: x -1  : x + 5

Product of means  = Product of extremes

(x + 12)(x -1) = (x +4)(x+5)

Use FOIL method for polynomial multiplication

x*x + x*(-1) + 12*x + 12*(-1) = x*x +  x*5  + 4*x + 4*5

x² - x + 12x - 12 = x² + 5x + 4x + 20

Combine like terms

x² + 11x - 12 = x² + 9x + 20

x² + 11x - 12 - x² - 9x - 20 = 0

Combine like terms

x² - x² + 11x -9x   -12 -20 = 0

2x - 32 = 0

2x = 32

x = 32/2

x = 16

5 0
2 years ago
Solve this system of linear equations. Separate
attashe74 [19]

Answer:

(-\frac{7}{13},\frac{79}{13})

Step-by-step explanation:

Given:

Two equations are given.

- 7x + 3y = 22------(1)

4x + 2y = 10----------(2)

Solve equation 1 for y.

- 7x + 3y = 22

3y = 22+7x

y=\frac{22+7x}{3}-----------(3)

Now, we substitute y value in equation 2.

4x + 2(\frac{22+7x}{3}) = 10

\frac{12x + 2(22+7x)}{3} = 10

12x + 2(22+7x)=10\times 3

12x + 44+14x=30

26x=30-44

26x=-14

x=-\frac{14}{26}

x=-\frac{7}{13}

Now, we substitute x value in equation 1.

- 7(-\frac{7}{13}) + 3y = 22

\frac{7\times 7}{13} + 3y = 22

\frac{49}{13} + 3y = 22

3y = 22-\frac{49}{13}

3y = \frac{13\times 22-49}{13}

3y = \frac{286-49}{13}

y = \frac{237}{13\times 3}

y = \frac{237}{39}

y = \frac{79}{13}

Therefore, the value of x and y is (x=-\frac{7}{13},y = \frac{79}{13})

7 0
4 years ago
Please help me! Please!
Mandarinka [93]

Answer:

here is your aneswer

the answer. will be 40

8 0
3 years ago
I don't get this. Can someone explain it better?
jarptica [38.1K]

Pick some number a. Then multiply this by another number r. Keep doing this and you generate a geometric sequence a,ar,ar^2,ar^3,\ldots.

The 11th and 12th terms in this sequence are then ar^{10} and ar^{11} (because you get the 11th term after you multiply by r 10 times, and the 12th term after 11 times).

The first term is, of course, a. We're given a=4 and r=\frac12. The sum of the 11th and 12th terms are then computed as shown in your picture.

8 0
3 years ago
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