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2 years ago

PLS HELP DO ALL PROBLEMS 100 PTS

Mathematics

1 answer:

padilas [110]2 years ago

3 0

Answer

4. - x ^ 2 + 13x - 42 <= 0524211r

5. x ^ 2 - 11x - 42 < 0

16 - x ^ 2 + 9x - 8 <= 0

17. x^ 2 -11x+80<0

18. - x ^ 2 + 3x + 4 <= 0

19. x ^ 2 - 12x + 36 <= 0

20. 2x ^ 2 - 32x + 56 < 0

21. x ^ 2 - 10x - 96 < 0

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If = 12 –3 a,find the value ofxwhen a= 8

faust18 [17]

Answer:

-12

Step-by-step explanation:

x = 12-3a

When a=8:

x = 12-3(8)

x = 12 - 24

x = -12

5 0

2 years ago

Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that

Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is $P(x_1 + x_2 \ge 2 )= 0.5940$

Step-by-step explanation:

From the question we are told that

The rate at which fire breaks out every 10 years is $\lambda = 1$

Generally the probability distribution function for Poisson distribution is mathematically represented as

$P(x) = \frac{\lambda^x}{ k! } * e^{-\lambda}$

Here x represent the number of state which is 2 i.e $x_1 \ \ and \ \ x_2$

Generally the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

$P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 + x_2 \le 1 )$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [ P(x_1 = 0 , x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)$

=> $P(x_1 + x_2 \ge 2 ) = 1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}$

=> $P(x_1 + x_2 \ge 2 )= 1- [[0.3678 * 0.3679] + [0.3678 * 0.3679] + [0.3678 * 0.3679] ]$

$P(x_1 + x_2 \ge 2 )= 0.5940$

3 0

3 years ago

the value of painting increases each year. To find the value of the painting for the next year, the art dealer multiplies the cu

Eva8 [605]

Answer:

the value of painting increases each year. To find the value of the painting for the next year, the art dealer multiplies the current value by 1.6. if the original value of the painting is 100, what is the value of the painting next yearStep-by-step explanation:

7 0

3 years ago

Help please and thank you

aksik [14]

Remember
$(a^b)^c=a^{bc}$
and
$\frac{x^a}{x^b}=x^{a-b}$

so

$\frac{(7^2)^5}{7^{-6}}=$
$\frac{7^{2*5}}{7^{-6}}=$
$\frac{7^{10}}{7^{-6}}=$
$7^{10-(-6)}=$
$7^{10+6}=$
$7^{16}$

the answer is D

5 0

4 years ago

Shen’s mother gave him $10 to go buy groceries. He picked up a gallon of milk for $3.49, three pounds of oranges that cost $1.14

svet-max [94.6K]

Gallon of milk: $3.49
3lbs oranges: $1.14(3) = $3.42
Box of cereal: $3.46

Front end estimation is taking the number in front and the rest of the numbers coming after it will be zeroes.

Using front end estimation:
$3.49 => $3.00
$3.42 => $3.00
$3.46 => $3.00

Add all these up; Shen estimated the total cost of the groceries would be $9.00.

5 0

4 years ago

Read 2 more answers