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3 years ago

PLS HELP DO ALL PROBLEMS 100 PTS

Mathematics

1 answer:

padilas [110]3 years ago

3 0

Answer

4. - x ^ 2 + 13x - 42 <= 0524211r

5. x ^ 2 - 11x - 42 < 0

16 - x ^ 2 + 9x - 8 <= 0

17. x^ 2 -11x+80<0

18. - x ^ 2 + 3x + 4 <= 0

19. x ^ 2 - 12x + 36 <= 0

20. 2x ^ 2 - 32x + 56 < 0

21. x ^ 2 - 10x - 96 < 0

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Help please ............

salantis [7]

Hey your BF is newstudier05

7 0

3 years ago

. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu

jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0

3 years ago

What is the GCF of 8 and 20<br> O 8<br> O2<br> O 4<br> O 10

Zielflug [23.3K]

What is the GCF of 8 and 20

Answer: 4

6 0

3 years ago

Out of 2,000 random but normally distributed numbers with a mean of 45 and a standard deviation of x, approximately 1,360 number

Lilit [14]

Let $Y$ denote the random variable representing a given number in the total set of numbers. We're told that $\dfrac{1360}{2000}=0.68$ of the numbers fall within a given range, so we know

$\mathbb P(40\le Y\le50)=0.68$

where $Y$ is normally distributed with mean 45 and an unknown variance $x^2$ .

Let's make the transformation to a random variable with a standard normal distribution:

$\mathbb P\left(\dfrac{40-45}x\le\dfrac{Y-45}x\le\dfrac{50-45}x\right)=\mathbb P\left(-\dfrac5x\le Z\le\dfrac5x\right)$

Since $Z$ is symmetric, we have

$\mathbb P(-\dfrac5x\le Z\le\dfrac5x\right)=2\mathbb P\left(0\le Z\le\dfrac5x\right)=2\bigg(\mathbb P\left(Z\le\dfrac5x\right)-\mathbb P(Z\le0)\bigg)$

The mean of $Z$ is 0, and by symmetry we know that exactly half of the distribution falls to the left of $Z=0$ , so $\mathbb P(Z\le0)=0.5$ . We're left with

$0.68=2\mathbb P\left(Z\le\dfrac5x\right)-2\cdot0.5$
$\implies\mathbb P\left(Z\le\dfrac5x\right)=0.84$

This probability corresponds to a value of $Z\approx0.9945$ , which means

$\dfrac5x\approx0.9945\implies x\approx5.0277$

7 0

3 years ago

Anyone knows the answers with their explanations

r-ruslan [8.4K]

Sorry that really confusing but i like your hand writing you did a really good job

8 0

4 years ago