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2 years ago

PLS HELP DO ALL PROBLEMS 100 PTS

Mathematics

1 answer:

padilas [110]2 years ago

3 0

Answer

4. - x ^ 2 + 13x - 42 <= 0524211r

5. x ^ 2 - 11x - 42 < 0

16 - x ^ 2 + 9x - 8 <= 0

17. x^ 2 -11x+80<0

18. - x ^ 2 + 3x + 4 <= 0

19. x ^ 2 - 12x + 36 <= 0

20. 2x ^ 2 - 32x + 56 < 0

21. x ^ 2 - 10x - 96 < 0

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Evaluate the function below for x=2. F(x)=2x^3-x^2-5x+6

Advocard [28]

$f(x)=2x^3-x^2-5x+6 \ \ \ \boxed{x=2}\\
\\
f(2)=2*2^3-2^2-5*2+6\\
\\
f(2)=16-4-10+6\\
\\
f(2)=8$

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3 years ago

Read 2 more answers

CAN YOU HELP ME PLEASEEEE ITS GEOMETRY!!!!! THANK YOUUU

agasfer [191]

If you divide 24/12 it’ll be 2 so either to find the sides you multiply or divide by 2 so if you’re trying to look for JK 8•2 = 16 and QS 16/2 = 8

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3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

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3 years ago

Someone please help me with this one quick

astraxan [27]

The length of AC is 16 km.

Solution:

Given data:

AB = c = 14 km, ∠A = 30° and ∠B = 89°

AC = b = ?

Let us first find angle C:

Sum of all angles in a triangle = 180°

m∠A+ m∠B + m∠C = 180°

30° + 89° + m∠C = 180°

119° + m∠C = 180°

Subtract 119° from both sides, we get

m∠C = 61°

To find the length of AC:

Using sine formula:

$$\frac{b}{\sin B } =\frac{c}{\sin C}$

Substitute the given values in the formula.

$$\frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ }$

Multiply by sin 89° on both sides.

$$\sin 89^\circ \times \frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ } \times \sin 89^\circ$

$$b=\frac{14}{0.8746 } \times0.9998$

$b=16$

The length of AC is 16 km.

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3 years ago

Which is the graph of the function f(x)= x^3 - 3x^2 - 4x?

Galina-37 [17]

TIP:

If you ever need to find the graph of a function, simply plug the function into the desmos graphing calculator! :)

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3 years ago